Question

我有两个命名A和B的列表：

A = ["boy","girl","place","food"]
B = ["he","she","USA,UK","Pizza,Burger,Sushi"]

当用户输入“boy”时，我希望输出为“he”。简而言之，我希望列表A中元素的索引值被赋予列表B中相同索引的值。

A[0] == B[0]
A[1] == B[1]
A[2] == B[2]
A[3] == B[3]

这就是我想要的。如果我输入A [i]中给出的数据，输出应该是B [i]中给出的。谢谢。

Answer 1

您可以使用.index(input_string)检索用户输入的索引，然后调用B：

A = ["boy","girl","place","food"]
B = ["he","she","USA,UK","Pizza,Burger,Sushi"]

i = A.index('boy')
print B[i]  # he

我认为您需要考虑将 dict 合并到这些列表中。

my_dict = dict(zip(A, B))

user_input = raw_in-put('enter a word\n')
if user_input in my_dict:
    print my_dict[user_input]

Answer 2

我可以使用额外的字典将A的值作为B值的键。

请查看以下示例以获取更多参考资料

A = ["boy","girl","place","food"]
B = ["he","she","USA,UK","Pizza,Burger,Sushi"]

dic = zip(A, B)

print(dic["boy"])

希望这有帮助！

Answer 3

首先，您必须检查您的输入是否确实在A中。然后，如果是，使用index方法找到A中项目的索引，则使用它访问B.

A = ["boy","girl","place","food"]
B = ["he","she","USA,UK","Pizza,Burger,Sushi"]
input_string = 'place'

if input_string in A:
    output_string = B[A.index(input_string)]
    print(output_string)  # outputs 'USA,UK'

Answer 4

理想情况下，您将数据构建为列表列表，因为就像现在一样，在不知道需要哪些组的情况下格式化字典非常困难：

A = ["boy","girl","place","food"]
B = ["he","she",["USA,UK"],["Pizza,Burger,Sushi"]]
new_data = {a:b for a, b in zip(A, B)}
print(new_data["boy"])

输出：

"he"

Answer 5

你绝对想要一个字典。

a_to_b = dict(zip(a,b))
print a_to_b['he'] == 'boy'

for key in a:
    print key, a_to_b[key]

如何在python中将数组的索引值赋给其他数组相同的索引值

5 个答案: