list comprehension结合2个列表

Question

我有两个序列如下

t = [[1,2,3],[4,5,6],[7,8,9]]
alpha = ['a','b','c']

如何使用列表推导来修改t如下： -

t = [[1,2,3,'a'],[4,5,6,'b'],[7,8,9,'c']]

Answer 1

您可以使用zip获取相应的元素对，并且从那里只需要加入：

>>> t = [[1,2,3],[4,5,6],[7,8,9]]
>>> alpha = ['a','b','c']
>>> [x[0] + [x[1]] for x in zip(t,alpha)]
[[1, 2, 3, 'a'], [4, 5, 6, 'b'], [7, 8, 9, 'c']]

Answer 2

使用zip：

t = [[1,2,3],[4,5,6],[7,8,9]]
alpha = ['a','b','c']
new_list = [a+[b] for a, b in zip(t, alpha)]

输出：

[[1, 2, 3, 'a'], [4, 5, 6, 'b'], [7, 8, 9, 'c']]

Answer 3

迭代指数：

t = [[1,2,3],[4,5,6],[7,8,9]]
alpha = ['a','b','c']
print([t[i] + [alpha[i]] for i in range(len(alpha))])