从JSON

Question

我有一个外部JSON文件，并且在Web应用程序中供内部使用时，我必须使用外部服务器的主JSON中的所有选定对象创建自定义和separte JSON字符串。

输出字符串应如下所示，但有更多对象：

{"geometry": {"type": "Point", "coordinates": [78.454, 22.643]}, "type": "Feature", "properties": {}}

创建字符串的jquery代码如下所示：

$.getJSON(getshowObjectReportExtern, function(data) {
$.each(data, function(key, value) {

// loop html table

}   

var llrealTimeObj = {
geometry: {
    type: 'FeatureCollection',
    features: [
        { // loop from here
        type: 'Feature',
        geometry: {
            type: 'Point',
            coordinates: [ value.latitude_mdeg, value.longitude_mdeg]
            },
        properties: {
            Number: value.objectno,
            Plate: value.objectname,
            Location: value.postext_short
            }
        }, // till there
    ]
  }
}


var llrealTimeJSONString = JSON.stringify(llrealTimeObj);
    console.log(llrealTimeJSONString);

});

为每个单个对象创建字符串工作正常，但目前问题是，我不知道如何创建包含外部JSON中所有选定对象的单个字符串。

对我有什么建议吗？提前谢谢！

编辑： 最终输出应该看起来像这样，但是使用我的主JSON文件中的对象。

{
 "type": "FeatureCollection",
 "features": [
    {
      "type": "Feature",
  "geometry": {
    "type": "Point",
    "coordinates": [
      -22.054688930511475,
      29.53522956294847
    ]
  },
  "properties": {}
},
{
  "type": "Feature",
  "geometry": {
    "type": "Point",
    "coordinates": [
      -22.933595180511475,
      19.642587534013032
    ]
  },
  "properties": {}
},
{
  "type": "Feature",
  "geometry": {
    "type": "Point",
    "coordinates": [
      -25.394532680511475,
      28.76765910569123
    ]
  },
  "properties": {}
}
  ]
}

链接到在线编辑器：https://google-developers.appspot.com/maps/documentation/utils/geojson/

Answer 1

假设数据是从外部源带来的JSON数组。

＆＃13;

＆＃13;

//jsonData is the external data I get from server
        var jsonData =
            {
                "type": "FeatureCollection",
                "features": [
                    {
                        "type": "Feature",
                        "geometry": {
                            "type": "Point",
                            "coordinates": [
                                -54.9904990196228,
                                -7.88514728342433
                            ]
                        },
                        "properties": {}
                    },
                    {
                        "type": "Feature",
                        "geometry": {
                            "type": "Point",
                            "coordinates": [
                                -54.9026083946228,
                                -13.752724664396975
                            ]
                        },
                        "properties": {}
                    },
                    {
                        "type": "Feature",
                        "geometry": {
                            "type": "Point",
                            "coordinates": [
                                -49.7170615196228,
                                -16.214674588248542
                            ]
                        },
                        "properties": {}
                    }
                ]
            };

        //My custome object
        var llrealTimeObj = {
            geometry: {
                type: 'FeatureCollection',
                features: []
            }
        };

        //Loop through external data
        $.each(jsonData.features, function (i, node) {
            llrealTimeObj.geometry.features.push({
                type: node.type,
                geometry: node.geometry //Add any more properties that you like here.
            });
        });

        var llrealTimeJSONString = JSON.stringify(llrealTimeObj);
        console.log(llrealTimeJSONString);

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script>

＆＃13;

＆＃13;

＆＃13;

Answer 2

我从同事那里得到了一个创建字符串的提示。 请参阅以下解决方案：

    $.getJSON(getshowObjectReportExtern, function(data) {
    var vehicleListData = '';
    var tmpLlrtArr = [];
    $.each(data, function(key, value) {

        // loop html table

        var tmpLlrtObj = {};
        tmpLlrtObj.type = 'Feature';
        tmpLlrtObj.geometry = {};
        tmpLlrtObj.geometry = {};
        tmpLlrtObj.geometry.type = 'Point';
        tmpLlrtObj.geometry.coordinates = [(value.longitude_mdeg * 0.000001).toFixed(6), (value.latitude_mdeg * 0.000001).toFixed(6)];
        tmpLlrtObj.properties = {};
        tmpLlrtObj.properties.VNumber = value.objectno;
        tmpLlrtObj.properties.Plate = value.objectname;
        tmpLlrtObj.properties.Position = value.postext_short;

        tmpLlrtArr.push(tmpLlrtObj);

    });


    var llrealTimeObj = {
      "type": "FeatureCollection",
      "features": tmpLlrtArr
    }


    var llrealTimeJSONString = JSON.stringify(llrealTimeObj);
        console.log(llrealTimeObj);


    $('#vehicleList').html(vehicleListData);

});