Question

我有一个javaScript脚本，如下所示：

$.ajaxFileUpload({
        url: url,
        secureuri: false, 
        fileElementId: ['upload-file'], 
        dataType: "JSON", 
        data:{ "sample_path":$(".demo-view-container-left .view img").attr("src")},
        success: function (data)  
        {
            data=JSON.parse(data);
            json = JSON.stringify(data.prediction, undefined, 4)
            var c=document.getElementById("myCanvas");
            var cxt=c.getContext("2d");
            var cxt_text=c.getContext("2d");
            for(var i=0; i<data.prediction.length; ++i){
              score_location=data.prediction[i][i.toString()]
              location=score_location['location']
              cxt.moveTo(location['left'], location['top']);
              cxt.lineTo(location['left']+location['width'], location['top']);
              cxt.lineTo(location['left']+location['width'], location['top']+location['height']);
              cxt.lineTo(location['left'], location['top']+location['height']);
              cxt.lineTo(location['left'], location['top']);
              cxt.stroke();
              cxt_text.font="12px";
              cxt_text.fillText(score_location['score'].toString(), location['left'], location['top']);
            }
            $(".demo-view-container-right p").html("预测JSON:<br>"+json)
        },
        error: function (data)
        {  
        }

它可以进入success部分并执行所有行，但最后它会转到一个新的URL，这是当前URL附加[object%20Object]导致404错误。如何解决这个问题呢？谢谢。

Answer 1

您正在导航，因为以下行是

location=score_location['location'] <-- that is the line that is doing it.

位置指向widow.location，所以你正在做

window.location = { ... }

当你不使用var并且变量对窗口对象有意义时会发生这种情况。所以声明它

var location = score_location['location']

使用ajaxFileUpload时出现[object％20Object]错误

1 个答案: