Question

尝试将swift对象解析为JSON数据时，我遇到了一个奇怪的问题。

长话短说：我的对象的属性都声明为Optional：

import Foundation

struct SrmaTaskStruct : JSONSerializable{
    var workOrderID : Int?
    var taskNum : Int?
    var taskName: String?
    var editable : Bool?
    var project : SrmaProjectStruct?
    var dates : [String]?
    var realizacije : [RealizacijaStruct]?

    var pctOfCompletionTask: CLong?
    var creationDate: Date?
    var createdBy: String?
    var lastUpdateDate: Date?
    var lastUpdatedBy: String?
    var endEstimate: Date?
    var endWork: Date?
    var minuteEstimate: CLong?
    var minuteWork: CLong?
    var startEstimate: Date?
    var startWork: Date?
    var priority: CLong?
    var text: String?
    var solution: String?
    var idRoleSpecialist: CLong?
    var idRoleSpecialistAssign: CLong?
    var idWorkType: CLong?
    var idMetActivity: CLong?
    var urgent: String?

    init(workOrderID: Int?, taskNum : Int?, taskName : String?, editable : Bool?, project : SrmaProjectStruct, dates : [String]?, realizacije : [RealizacijaStruct]?) {
        self.workOrderID = workOrderID
        self.taskNum = taskNum
        self.taskName = taskName
        self.editable = editable
        self.project = project
        self.dates = dates
        self.realizacije = realizacije
        self.idMetActivity = 0
    }

    init(workOrderID: Int?, idMetActivity: CLong?, idWorkType: CLong?, urgent: String?, idRoleSpecialistAssign: CLong?, idRoleSpecialist: CLong?,
         startEstimate: Date?, endEstimate: Date?, minuteEstimate: CLong?, pctOfCompletionTask: CLong?, text: String?) {
        self.workOrderID = workOrderID
        self.idMetActivity = idMetActivity
        self.idWorkType = idWorkType
        self.urgent = urgent
        self.idRoleSpecialistAssign = idRoleSpecialistAssign
        self.idRoleSpecialist = idRoleSpecialist
        self.startEstimate = startEstimate
        self.endEstimate = endEstimate
        self.minuteEstimate = minuteEstimate
        self.pctOfCompletionTask = pctOfCompletionTask
        self.text = text

    }

}

，在初始化期间，其中一些设置为非可选值：

var task = SrmaTaskStruct(workOrderID: (workOrder?.workOrderId)!, idMetActivity: CLong((discipline?.disciplineId)!), idWorkType: CLong((discipline?.workTypeId)!), urgent: urgent, idRoleSpecialistAssign: CLong((employer?.roleId)!), idRoleSpecialist: CLong((employee?.roleId)!), startEstimate: startEstimate!, endEstimate: endEstimate!, minuteEstimate: minuteEstimate!, pctOfCompletionTask: CLong(0), text: text!)

然后，我调用JSONSerializable toJSON（）：

let jsonData = task.toJSON()!

与this article一致的功能。结果，我得到了

 function signature specialization <preserving fragile attribute, Arg[1] = [Closure Propagated : reabstraction thunk helper from @callee_owned (@unowned Swift.UnsafeBufferPointer<Swift.UInt8>) -> () to @callee_owned (@unowned Swift.UnsafeBufferPointer<Swift.UInt8>) -> (@out ()), Argument Types : [@callee_owned (@unowned Swift.UnsafeBufferPointer<Swift.UInt8>) -> ()]> of generic specialization <preserving fragile attribute, ()> of Swift.StaticString.withUTF8Buffer <A> ((Swift.UnsafeBufferPointer<Swift.UInt8>) -> A) -> A

异常，因为这段代码

guard JSONSerialization.isValidJSONObject(representation) else {
            return nil
}

在toJSON（）函数中

返回nil。

对我来说，看起来JSONSerialization.isValidJSONObject（）函数因为Optional属性而返回false，但我不明白为什么会发生这种情况，因为它适用于其他情况。

我错过了什么？有人可以帮忙吗？

尝试将对象解析为JSON数据时Swift.UnsafeBufferPointer <swift.uint8>异常

0 个答案: