Question

我在下面写了表和SQL查询，这个查询不应该返回任何结果但返回ID = 1，SQL查询有什么问题？有人可以帮忙吗？

**注意balance数据类型为decimal，其余为varchar

ID  code    balance level
1   C   150.00  
1   P   40027.42    F
1   P   40027.42    F

select distinct ID from table
(
(code = 'P' and balance = 40027.42 and level = 'F') or
(code  = 'C' and balance = 151.00 )
)
group by ID
having count(ID) >=2

Answer 1

如果您不想计算两次相同的code，可以使用count(distinct code)：

select ID 
from t
where (code = 'P' and balance = 40027.42 and level = 'F') 
  or (code  = 'C' and balance = 151.00 )
group by ID
having count(distinct code) >=2

如果您只想计算一组不同的值，可以将派生表/子查询用于select distinct行：

select ID 
from (
  select distinct id, code, balance, level 
  from t
  ) as s
where (code = 'P' and balance = 40027.42 and level = 'F') 
  or (code  = 'C' and balance = 151.00 )
group by ID
having count(ID) >=2

两者的rextester演示：http://rextester.com/LBKO57534

MS SQL查询跨行的多个搜索条件

1 个答案: