Question

我有一个Node服务器，其中包含以下代码：

var server = require('http').createServer(handler);
var io = require('socket.io')(server);
var fs = require('fs');

function handler(request,response) {
    if (request.url == '/123') {
         // The following line says that socket is undefined.
         //socket.emit('case_updated', 123);
    }
    response.writeHead(200, {'Location' : '/'});
    return response.end('');
}

io.sockets.on('connection', function (socket) {
    socket.on('case_updated', function(caseNumber){
        socket.broadcast.emit('case_updated', caseNumber);
    });
});

server.listen(3000);

现在，我希望在访问该URL时触发socket.broadcast.emit。

Answer 1

找到问题的解决方案。

我刚刚在服务器所在的同一个地方安装了socket.io-client软件包，并在服务器代码中实例化了客户端，并且我能够使用socket.emit函数。在if语句中的handler函数中，我正在创建一个客户端。

var server = require('http').createServer(handler);
var io = require('socket.io')(server);
var fs = require('fs');

function handler(request,response) {
    if (request.url == '/123') {
        //192.168.2.100 is the ip of the same server where this code is located.
        var socket_client = require("socket.io-client")('http://192.168.2.100:3000');
        socket_client.on('connect', function () {
            socket_client.emit('case_updated', 123);
        });
    }
    response.writeHead(200, {'Location' : '/'});
    return response.end('');
}

io.sockets.on('connection', function (socket) {
    socket.on('case_updated', function(caseNumber){
        socket.broadcast.emit('case_updated', caseNumber);
    });
});

server.listen(3000);

SocketIO：从URL更新连接的套接字

1 个答案: