Question

当我尝试执行My Lines of Code

时

//使用Staements

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading;
using System.Threading.Tasks;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;
using TwitchLib;
using TwitchLib.Events.Client;
using TwitchLib.Models.Client;

//我的代码行

void PostMessage(string UserName,string UserType, bool isSub, string Message)
{
    StackPanel SP = new StackPanel();
    SP.Orientation = Orientation.Horizontal;
    TextBlock DT = new TextBlock();
    DT.Text = DateTime.Now.ToShortTimeString();
    SP.Children.Add(DT);
    TextBlock Caster = new TextBlock();
    TextBlock Type = new TextBlock();
    switch (UserType)
    {
        case "Broadcaster":
            Caster.Text = " CASTER ";
            SP.Children.Add(Caster);
            Type.Text = " MOD ";
            SP.Children.Add(Type);
            break;
        case "Moderator":
            Type.Text = " MOD ";
            SP.Children.Add(Type);
            break;
        case "GlobalModerator":
            Type.Text = " GMOD ";
            SP.Children.Add(Type);
            break;
        case "Staff":
            Type.Text = " STAFF ";
            SP.Children.Add(Type);
            break;
        case "Admin":
            Type.Text = " ADMIN ";
            SP.Children.Add(Type);
            break;
        default:
            break;
    }
    if (isSub == true)
    {
        TextBlock Sub = new TextBlock();
        Sub.Text = " SUB ";
        SP.Children.Add(Sub);
    }
    TextBlock UName = new TextBlock();
    SP.Children.Add(UName);
    UName.Text = " " + UserName + ": ";
    TextBlock Mess = new TextBlock() ;
    Mess.Text = Message;
    SP.Children.Add(Mess);
    //ChatWindow.Text += DT + pretag + UserName + Message + Environment.NewLine;
    ChatWindow.Dispatcher.Invoke(new Action(() => ChatWindow.Items.Add(SP)));
}

我拉这个异常“调用线程必须是STA，因为许多UI组件都需要这个。”

如果我试试这个

void PostMessage(string UserName,string UserType, bool isSub, string Message)
{
Thread thread = new Thread(() => {
    //Same inside Code
});
thread.SetApartmentState(ApartmentState.STA);
thread.Start();
}

我拉出异常'调用线程无法访问此对象，因为另一个线程拥有它。'

基本上它把对待就好像调用从未发生过一样有些人可以给我一些建议。我是使用WPF的新手。

wpf STA线程和

0 个答案: