Question

这是我所拥有的以下数据库结构，这里是我们面临的问题，即根据提交的方式对行进行排序。

字段 - 表格保存字段信息ed，2002,2015，Region 1等

IndicatorData - 保留行数据

datafield - 与IndicatorData表的关系...行可以有多个字段

/****** object:  table [dbo].[indicatordata] ******/ 
create table [dbo].[indicatordata](
    [id] [bigint] null,
    [value] [decimal](18, 2) null,
    [hopevalue] [decimal](18, 2) null,
    [indicatorid] [int] null,
    [datakind] [int] null
) on [primary]
go
insert [dbo].[indicatordata] ([id], [value], [hopevalue], [indicatorid], [datakind]) values (195045, cast(70.00 as decimal(18, 2)), cast(0.00 as decimal(18, 2)), 2032, 0)
insert [dbo].[indicatordata] ([id], [value], [hopevalue], [indicatorid], [datakind]) values (195046, cast(40.00 as decimal(18, 2)), cast(0.00 as decimal(18, 2)), 2032, 0)
insert [dbo].[indicatordata] ([id], [value], [hopevalue], [indicatorid], [datakind]) values (195047, cast(5.00 as decimal(18, 2)), cast(0.00 as decimal(18, 2)), 2032, 0)
insert [dbo].[indicatordata] ([id], [value], [hopevalue], [indicatorid], [datakind]) values (195048, cast(100.00 as decimal(18, 2)), cast(0.00 as decimal(18, 2)), 2032, 0)
insert [dbo].[indicatordata] ([id], [value], [hopevalue], [indicatorid], [datakind]) values (195049, cast(87.00 as decimal(18, 2)), cast(0.00 as decimal(18, 2)), 2032, 0)
insert [dbo].[indicatordata] ([id], [value], [hopevalue], [indicatorid], [datakind]) values (195050, cast(9.00 as decimal(18, 2)), cast(0.00 as decimal(18, 2)), 2032, 0)
/****** object:  table [dbo].[indicator]  ******/
go
create table [dbo].[indicator](
    [id] [int] null,
    [name] [varchar](50) null
) on [primary]
go
insert [dbo].[indicator] ([id], [name]) values (2032, n'test tile')
/****** object:  table [dbo].[field]    ******/
 go
create table [dbo].[field](
    [id] [int] null,
    [name] [varchar](255) null,
    [rank] [int] null,
    [parentid] [int] null
) on [primary]
go
insert [dbo].[field] ([id], [name], [rank], [parentid]) values (120, n'2006', 18, 57)
insert [dbo].[field] ([id], [name], [rank], [parentid]) values (63, n'2015', 17, 57)
insert [dbo].[field] ([id], [name], [rank], [parentid]) values (303, n'2007', 9, 57)
insert [dbo].[field] ([id], [name], [rank], [parentid]) values (168, n'2018', 20, 57)
insert [dbo].[field] ([id], [name], [rank], [parentid]) values (1463, n'region 1', 1, 1459)
insert [dbo].[field] ([id], [name], [rank], [parentid]) values (1461, n'region 2', 3, 1459)
insert [dbo].[field] ([id], [name], [rank], [parentid]) values (57, n'year', 0, 0)
insert [dbo].[field] ([id], [name], [rank], [parentid]) values (1459, n'region', 0, 0)
insert [dbo].[field] ([id], [name], [rank], [parentid]) values (315, n'2002', 1, 57)
insert [dbo].[field] ([id], [name], [rank], [parentid]) values (123, n'2017', 19, 57)
/****** object:  table [dbo].[datafields]     ******/
set ansi_nulls on
go
create table [dbo].[datafields](
    [dataid] [int] null,
    [fieldid] [int] null
) on [primary]
go
insert [dbo].[datafields] ([dataid], [fieldid]) values (195045, 120)
insert [dbo].[datafields] ([dataid], [fieldid]) values (195045, 1463)
insert [dbo].[datafields] ([dataid], [fieldid]) values (195046, 63)
insert [dbo].[datafields] ([dataid], [fieldid]) values (195046, 1461)
insert [dbo].[datafields] ([dataid], [fieldid]) values (195047, 303)
insert [dbo].[datafields] ([dataid], [fieldid]) values (195047, 1463)
insert [dbo].[datafields] ([dataid], [fieldid]) values (195048, 168)
insert [dbo].[datafields] ([dataid], [fieldid]) values (195048, 1463)
insert [dbo].[datafields] ([dataid], [fieldid]) values (195049, 315)
insert [dbo].[datafields] ([dataid], [fieldid]) values (195049, 1463)
insert [dbo].[datafields] ([dataid], [fieldid]) values (195050, 123)
insert [dbo].[datafields] ([dataid], [fieldid]) values (195050, 1463)
go

以下是我试图将其归档的查询。但它失败了

    select fieldid, groupedData.value as value, groupedData.hopeValue as hopeValue, 
groupedData.datakind, groupedData.id as id, FieldSelector.name,
 groupedData.rank
from DataFields FieldsToInsert
join (
select d.id id,min(d.datakind) as datakind, sum(rank) rank, min(value) value, min(hopeValue) hopeValue 
from indicatorData d join datafields df on d.id = df.dataid
  join field f  on df.fieldId=f.id  where indicatorId=2032 
group by d.id) groupedData on FieldsToInsert.dataid = groupedData.id 
join Field FieldSelector  on FieldSelector.id=FieldsToInsert.fieldId
order by  groupedData.rank asc, groupedData.id

我们得到的输出是 View Image

期望输出是 View image

Answer 1

所以第一个让我感到震惊的是＃34;数据是否正确？＆＃34;我问，因为看看年份和排名值，它表明2006年应该是2016年，或者2006年的排名应该是8而不是18。

除此之外，假设数据正确，您需要将该地区与适当的年份相关联。您可以通过获取字段记录的父名称并包含fieldid然后自行加入以获取该fieldid区域记录的关联年份来执行此操作...

WITH GroupedData AS
(            SELECT   d.id id,
                      min(d.datakind) AS datakind,
                      sum(f.rank) rank,
                      min(d.value) value,
                      min(d.hopevalue) hopeValue
             FROM     indicatordata d
             JOIN     datafields df ON d.id = df.dataid
             JOIN     field f ON df.fieldid = f.id
             WHERE    d.indicatorid = 2032
             GROUP BY d.id
)
,  df_parentType AS 
(   SELECT df.dataid,
           df.fieldid,
           f.name,
           f.rank,
           f.parentid,
           fy.name AS parentname
    FROM dbo.datafields AS df
    JOIN field AS f ON df.fieldid = f.Id
    JOIN field AS fy ON f.parentId = fy.Id
)
, df_yearregionmatched AS
(   SELECT df.dataid,
           df.fieldid,
           df.name,
           df.rank,
           dfp.name AS yearname,
           CASE df.parentname WHEN 'year' THEN 0 ELSE 1 END AS datafieldtype
    FROM df_parentType AS df
    JOIN df_parentType AS dfp ON dfp.dataid = df.dataid AND dfp.parentname = 'year'
)
SELECT   GroupedData.id AS fieldid,
         GroupedData.value AS value,
         GroupedData.hopeValue AS hopeValue,
         GroupedData.datakind,
         GroupedData.id AS id,
         FieldSelector.name,
         GroupedData.rank,
         FieldSelector.yearname,
         FieldSelector.datafieldtype
FROM     GroupedData
JOIN     df_yearregionmatched FieldSelector ON GroupedData.id = FieldSelector.dataid
ORDER BY FieldSelector.yearname,
         FieldSelector.datafieldtype;

我使用CTE来保持代码简单。然后，顺序只是通过年名和生成的值，将年份放在区域之前。

Answer 2

<强> @nickFry 使用复杂的示例再检查另一个字段...

     create table indicator(id int not null,name varchar(255) not null)
insert indicator (id, name) values (1, 'basic employee details')

create table fields(
id int not null,  
rank int,
name varchar(255) not null,
parentid int not null)

insert fields (id, rank, name, parentid) values (1, 0, 'year', 0)
insert fields (id, rank, name, parentid) values (2, 1, '2010', 1)
insert fields (id, rank, name, parentid) values (5, 2, '2011', 1)
insert fields (id, rank, name, parentid) values (6, 3, '2012', 1)
insert fields (id, rank, name, parentid) values (7, 4, '2013', 1)
insert fields (id, rank, name, parentid) values (8, 5, '2014', 1)

insert fields (id, rank, name, parentid) values (9, 0, 'nationality', 0)
insert fields (id, rank, name, parentid) values (10, 1, 'libya', 9)
insert fields (id, rank, name, parentid) values (11, 2, 'ukrine', 9)

insert fields (id, rank, name, parentid) values (12, 0, 'gender', 0)
insert fields (id, rank, name, parentid) values (13, 1, 'male', 12)
insert fields (id, rank, name, parentid) values (14, 2, 'fe male', 12)

insert fields (id, rank, name, parentid) values (15, 0, 'maritalstatus', 0)
insert fields (id, rank, name, parentid) values (16, 1, 'married', 15)
insert fields (id, rank, name, parentid) values (17, 2, 'unmarried', 15)
insert fields (id, rank, name, parentid) values (18, 3, 'divorced', 15)


create table indicatorfields(
indicatorid int not null,
fieldid int not null,rank int)

insert indicatorfields (indicatorid, fieldid,rank) values (1, 2,1)
insert indicatorfields (indicatorid, fieldid,rank) values (1, 5,1)
insert indicatorfields (indicatorid, fieldid,rank) values (1, 6,1)
insert indicatorfields (indicatorid, fieldid,rank) values (1, 7,1)
insert indicatorfields (indicatorid, fieldid,rank) values (1, 8,1)
insert indicatorfields (indicatorid, fieldid,rank) values (1, 10,3)
insert indicatorfields (indicatorid, fieldid,rank) values (1, 11,3)
insert indicatorfields (indicatorid, fieldid,rank) values (1, 16,2)
insert indicatorfields (indicatorid, fieldid,rank) values (1, 17,2)
insert indicatorfields (indicatorid, fieldid,rank) values (1, 18,2)


create table indicatordata(
dataid int not null,
value varchar(255) not null,
indicatorid int not null) 

insert indicatordata (dataid, value, indicatorid) values (1, '1015', 1)
insert indicatordata (dataid, value, indicatorid) values (2, '15', 1)
insert indicatordata (dataid, value, indicatorid) values (3, '12', 1)
insert indicatordata (dataid, value, indicatorid) values (4, '187', 1)
insert indicatordata (dataid, value, indicatorid) values (5, '50', 1)
insert indicatordata (dataid, value, indicatorid) values (6, '65', 1)

create table datafields(
    dataid int not null,
    fieldid int not null)

insert datafields (dataid, fieldid) values (1, 8)
insert datafields (dataid, fieldid) values (1, 10)
insert datafields (dataid, fieldid) values (1, 16)

insert datafields (dataid, fieldid) values (2, 6)
insert datafields (dataid, fieldid) values (2, 11)
insert datafields (dataid, fieldid) values (2, 17)

insert datafields (dataid, fieldid) values (3, 7)
insert datafields (dataid, fieldid) values (3, 11) 
insert datafields (dataid, fieldid) values (3, 17)

insert datafields (dataid, fieldid) values (4, 2)
insert datafields (dataid, fieldid) values (4, 11)
insert datafields (dataid, fieldid) values (4, 16)

insert datafields (dataid, fieldid) values (5, 8)
insert datafields (dataid, fieldid) values (5, 10)
insert datafields (dataid, fieldid) values (5, 18)

insert datafields (dataid, fieldid) values (6, 2)
insert datafields (dataid, fieldid) values (6, 10)
insert datafields (dataid, fieldid) values (6, 16)

我们需要根据指标字段＆amp;获取行。字段表按排名顺序

参见附图实际产出

这是我正在寻找的期待OutPut

Answer 3

@Prasad，解决方案，不参考任何硬编码数据值......

WITH GroupedData AS
(            SELECT   d.dataid id,
                      --min(d.datakind) AS datakind,
                      sum(f.rank) rank,
                      min(d.value) value --,
                      --min(d.hopevalue) hopeValue
             FROM     indicatordata d
             JOIN     datafields df ON d.dataid = df.dataid
             JOIN     fields f ON df.fieldid = f.id
             WHERE    d.indicatorid = 1
             GROUP BY d.dataid
)
,  df_parentType AS 
(   SELECT df.dataid,
           df.fieldid,
           f.name,
           f.rank,
           f.parentid,
           fy.name AS parentname
    FROM dbo.datafields AS df
    JOIN fields AS f ON df.fieldid = f.Id
    JOIN fields AS fy ON f.parentId = fy.Id
)
, df_parentmatched AS
(   SELECT df.dataid,
           df.fieldid,
           df.name,
           df.rank,
           dfp.name AS parentname
    FROM df_parentType AS df
    JOIN df_parentType AS dfp ON dfp.dataid = df.dataid AND dfp.parentname = (SELECT DISTINCT parentname FROM df_parentType WHERE parentid = (SELECT min(dataid) FROM df_parentType))
)
SELECT   GroupedData.id AS datadid,
         GroupedData.value AS value,
         --GroupedData.hopeValue AS hopeValue,
         --GroupedData.datakind,
         FieldSelector.fieldid,
         FieldSelector.name,
         GroupedData.rank,
         FieldSelector.parentname
FROM     GroupedData
JOIN     df_parentmatched FieldSelector ON GroupedData.id = FieldSelector.dataid
ORDER BY FieldSelector.parentname,
         GroupedData.rank,
         FieldSelector.fieldid;

Answer 4

@nickFy 你提供的那个很好......有了这个复杂的例子......预期的顺序没有以正确的方式出现

这是另一个没有年份的复杂例子

insert indicator (id, name) values (2, 'testing employee details 2')


insert indicatorfields (indicatorid, fieldid,rank) values (2, 10,3)
insert indicatorfields (indicatorid, fieldid,rank) values (2, 11,3)

insert indicatorfields (indicatorid, fieldid,rank) values (2, 13,1)
insert indicatorfields (indicatorid, fieldid,rank) values (2, 14,1)

insert indicatorfields (indicatorid, fieldid,rank) values (2, 16,2)
insert indicatorfields (indicatorid, fieldid,rank) values (2, 17,2)
insert indicatorfields (indicatorid, fieldid,rank) values (2, 18,2)


insert indicatordata (dataid, value, indicatorid) values (7, '1015', 2)
insert indicatordata (dataid, value, indicatorid) values (8, '15', 2)
insert indicatordata (dataid, value, indicatorid) values (9, '12', 2)
insert indicatordata (dataid, value, indicatorid) values (10, '187', 2)
insert indicatordata (dataid, value, indicatorid) values (11, '50', 2)




insert datafields (dataid, fieldid) values (7, 11)
insert datafields (dataid, fieldid) values (7, 13)
insert datafields (dataid, fieldid) values (7, 16)

insert datafields (dataid, fieldid) values (8, 10)
insert datafields (dataid, fieldid) values (8, 13)
insert datafields (dataid, fieldid) values (8, 17)

insert datafields (dataid, fieldid) values (9, 10)
insert datafields (dataid, fieldid) values (9, 14) 
insert datafields (dataid, fieldid) values (9, 18)

insert datafields (dataid, fieldid) values (10, 11)
insert datafields (dataid, fieldid) values (10, 13)
insert datafields (dataid, fieldid) values (10, 16)

insert datafields (dataid, fieldid) values (11, 10)
insert datafields (dataid, fieldid) values (11, 14)
insert datafields (dataid, fieldid) values (11, 16)

**我们得到的实际输出是**

select a.dataid,value,df.fieldid,name from indicatordata a INNER JOIN datafields df on a.dataid=df.dataid
INNER JOIN fields f ON df.fieldid=f.id INNER JOIN indicatorfields indFields ON indFields.fieldid=df.fieldid
where a.indicatorid=2 and indFields.indicatorid=2 order by a.dataid

我们需要根据指标字段＆amp;字段表

预期输出应该是这样的

SQL命令行

4 个答案: