Question

在R中，如何在计算行之前的定义时间段内计算cumsum？如果可能的话，首选dplyr。

例如，如果期间为10天，那么该函数将实现cum_rolling10：

date    value   cumsum  cum_rolling10
1/01/2000   9   9       9
2/01/2000   1   10      10
5/01/2000   9   19      19
6/01/2000   3   22      22
7/01/2000   4   26      26
8/01/2000   3   29      29
13/01/2000  10  39      29
14/01/2000  9   48      38
18/01/2000  2   50      21
19/01/2000  9   59      30
21/01/2000  8   67      38
25/01/2000  5   72      24
26/01/2000  1   73      25
30/01/2000  6   79      20
31/01/2000  6   85      18

Answer 1

使用dplyr，tidyr，lubridate和zoo的解决方案。

library(dplyr)
library(tidyr)
library(lubridate)
library(zoo)

dt2 <- dt %>%
  mutate(date = dmy(date)) %>%
  mutate(cumsum = cumsum(value)) %>%
  complete(date = full_seq(date, period = 1), fill = list(value = 0)) %>%
  mutate(cum_rolling10 = rollapplyr(value, width = 10, FUN = sum, partial = TRUE)) %>%
  drop_na(cumsum)
dt2
# A tibble: 15 x 4
         date value cumsum cum_rolling10
       <date> <dbl>  <int>         <dbl>
 1 2000-01-01     9      9             9
 2 2000-01-02     1     10            10
 3 2000-01-05     9     19            19
 4 2000-01-06     3     22            22
 5 2000-01-07     4     26            26
 6 2000-01-08     3     29            29
 7 2000-01-13    10     39            29
 8 2000-01-14     9     48            38
 9 2000-01-18     2     50            21
10 2000-01-19     9     59            30
11 2000-01-21     8     67            38
12 2000-01-25     5     72            24
13 2000-01-26     1     73            25
14 2000-01-30     6     79            20
15 2000-01-31     6     85            18

数据

dt <- structure(list(date = c("1/01/2000", "2/01/2000", "5/01/2000", "6/01/2000", "7/01/2000", "8/01/2000", "13/01/2000", "14/01/2000", "18/01/2000", "19/01/2000", "21/01/2000", "25/01/2000", "26/01/2000", "30/01/2000", "31/01/2000"), value = c(9L, 1L, 9L, 3L, 4L, 3L, 10L, 9L, 2L, 9L, 8L, 5L, 1L, 6L, 6L)), .Names = c("date", "value" ), row.names = c(NA, -15L), class = "data.frame")

Answer 2

我建议使用runner软件包，该软件包旨在计算滚动/运行窗口上的函数。您可以使用sum_run-这里的一个衬里来实现这一点：

library(runner)
library(dplyr)

df %>%
  mutate(
    cum_rolling_10 = sum_run(
      x = df$value, 
      k = 10, 
      idx = as.Date(df$date, format = "%d/%m/%Y"))
  )


df

#          date value cum_rolling_10
# 1   1/01/2000     9              9
# 2   2/01/2000     1             10
# 3   5/01/2000     9             19
# 4   6/01/2000     3             22
# 5   7/01/2000     4             26
# 6   8/01/2000     3             29
# 7  13/01/2000    10             29
# 8  14/01/2000     9             38
# 9  18/01/2000     2             21
# 10 19/01/2000     9             30
# 11 21/01/2000     8             38
# 12 25/01/2000     5             24
# 13 26/01/2000     1             25
# 14 30/01/2000     6             20
# 15 31/01/2000     6             18

享受！

Answer 3

此解决方案将避免内存开销，并且迁移到sparklyr很容易。

滞后= 7

    dt %>%
  mutate(date = dmy(date)) %>%
  mutate(order = datediff(date,min(date)) %>% 
  arrange(desc(order)) %>% 
  mutate(n_order = lag(order + lag,1L,default = 0)) %>% 
  mutate(b_order = ifelse(order - n_order >= 0,order,-1)) %>% 
  mutate(m_order = cummax(b_order)) %>% 
  group_by(m_order) %>% 
  mutate(rolling_value = cumsum(value))

R：滚动日期范围内的累计和

3 个答案: