Question

我终于完成了这个代码，但是有一个问题：对于输出“Positions：”我希望它输出最小值发生的每个位置。但是，我的代码只输出每个随机生成的数组中的最小位置（大小为20）。请指导我如何在输出最小值的多个位置时减少冗余。谢谢！

#include <iostream>
#include <iomanip>
using namespace std;

double random(unsigned int &seed);
unsigned int seed = (unsigned int)time(0);
const int SIZE = 20;

void print_array (int a[]);
void fill_array (int a []);
int find_min (int [], int);

int main ()
{
  int arr[SIZE];
  cout << "Arrays: \n";
  fill_array(arr);
  print_array(arr);

  int pos = find_min(arr, SIZE); 
  int minimum = arr[pos];

  cout << "Min is: " << minimum << endl;
  cout << "At position: " << pos +1 << endl; 

  return 0;
  }

double random(unsigned int &seed)
{
   const int MODULUS = 15749;
   const int MULTIPLIER = 69069;
   const int INCREMENT = 1;
   seed = ((MULTIPLIER*seed)+INCREMENT)%MODULUS;
   return double(seed)/MODULUS;
   }

void fill_array (int a [])
{
   for (int i = 0; i < SIZE; ++i)
      a[i] = 0 + (10 * (random(seed)));
}

int find_min (int arr[], int n)
{
   int min = arr[0]; 
   int index = 0;

   for (int i = 1; i < n; ++i)
     if (arr[i] < min) 
     {
        index = i;
        min = arr[i];
     }
   return index;
 }

 void print_array (int a[])
 {
    for (int i = 0; i <SIZE; ++i)
      cout << setw(3) << a[i];
 cout << endl;
 }

Answer 1

您可以通过更改main来实现目标。请参阅以下代码

int main ()
{
  int arr[SIZE];
  cout << "Arrays: \n";
  fill_array(arr);
  print_array(arr);

  int pos = find_min(arr, SIZE); 
  int minimum = arr[pos];

  //The following loop traverses through the array and prints the position when array element is equals to minimum
  for (int i = pos; i < SIZE; i++) {
     if (arr[i] == minimum)
       cout << "Min is at: " << i+1 << endl;    
  }

  cout << "Min is: " << minimum << endl;
  cout << "At position: " << pos +1 << endl; 

  return 0;
}

已编辑：要在一行中打印，您可以执行以下代码 -

cout << "Min is at: "
for (int i = pos; i < SIZE; i++) {
         if (arr[i] == minimum) {

             if (i != pos) cout << ", ";

             cout << i+1 << endl;


         }

 }

但是，有许多格式选项。你可以使用它们中的任何一个。

如何使我的代码中的“position：”更精确？

1 个答案: