Question

我试图返回包含5的所有数字，包括起始值和结束值。我创建了一个包含所有数字的字符串列表。但是，我对如何获取值并将它们添加到新列表感到困惑。例如，giveMeFive（42,75）将返回列表[45,50,51,52,53,54,55,56， 57,58,59,65,75]

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Answer 1

在您的代码中，您正在执行：

lst = str(list(range(num1, num2 + 1)))

将列表转换为字符串，然后迭代字符串。相反，您的代码应该是：

lst = list(range(num1, num2 + 1))  # No need to type-cast it to string.
                                   # Infact you don't even need `list` here.
newLst = []
for x in lst:
    #          v type-cast your number to string
    if "5" in str(x):  # check "5" is present in your number string
         newLst.append(x)  # append your number to the list

实现这一目标的更好方法是通过 list comprehension 表达式。例如：

>>> number1 = 5
>>> number2 = 31

>>> [i for i in range(number1, number2+1) if "5" in str(i)]
[5, 15, 25]

Answer 2

这也有效

num1 = int(input("Input no 1"))
num2 = int(input("Input no 2"))

lst = map(str, range(num1, num2+1))
#         ^ convert list of numbers to list of "number strings"

List5 = []
for i in lst:
    if "5" in i:
        List5.append(i)

返回包含5的所有数字

2 个答案: