Question

我有一个班级Players。我想用Hyperlink和Skip方法创建Take。但是给了我System.Linq.Enumerable错误。我的目标是制作金字塔用户列表。这是我的代码

public class Players
{
    public string Name{ get; set; }
    public int Order{ get; set; }
    public int ID { get; set; }
}



List<Players> playerlist= new List<Players>();
playerlist= (from DataRow dr in dt.Rows
             select new Players()
             {
                 Name= (dr["name"].ToString()),
                 Order= int.Parse(dr["order"].ToString()),
                 ID = int.Parse(dr["Id"].ToString())
             }).ToList();

playerlist= playerlist.OrderBy(x => x.Order).ToList();

int skip = 0;
int take = 1;
int addedCount = 0;

do
{   
    HyperLink links= new HyperLink();
    links.Text = "" + playerlist.Skip(skip ).Take(take).Select(x => x.Name);
    links.NavigateUrl = "playerdetails.aspx?id=" + oyunculistesi.Skip(skip).Take(take).Select(x => x.ID);
    Page.Controls.Add(links);
    addedCount += take ;
    skip+= take ;
    take += +1;
}
while (addedCount < playerlist.Count);

它与StringBuilder合作，但HyperLink没有。

sb.AppendLine(string.Join(" ", players.Skip(skip).Take(take).Select(x => $"{x.Order}) {x.Name}")));

Answer 1

您的Select正在返回char string.Join，您需要使用StringBuilder来构建一个字符串，就像您在linkuret.Text = string.Join("" , playerlist.Skip(skip).Take(take).Select(x => x.Name));中所做的那样：

public class Lesson4OOP {
public static void main(String[] args) {
    String[] names = {"Adam","Sara", "Mike" , "David"};
    int[] ages = {21, 25, 34, 16};
    User[] users = new User[names.length];
    for(int i = 0; i<users.length; i++){
        User u = new User();
        u.setName(names[i]);
        users[i] = u;
    }

    for(int j = 0; j<ages.length; j++){
        User a = new User();
        a.setAge(ages[j]);
        users[j] = a;
    }
    System.out.println(users[3].getName());
    System.out.println(users[3].getAge());
    }
}

public class User {
    String names;
    int ages;

    public void setName(String val){
        names = val;
    }
    public String getName(){
        return names;
    }
    public void setAge(int num){
        ages = num;
    }
    public int getAge(){
        return ages;
    }
}

Answer 2

我会以这种方式重写你的循环

    int skip = 0;
    while (skip < playerlist.Count)
    {

        HyperLink links= new HyperLink();
        Players p = playerlist.Skip(skip).FirstOrDefault();
        links.Text = $"{p.Name}" 
        links.NavigateUrl = $"playerdetails.aspx?id={p.Id}"
        Page.Controls.Add(links);
        skip++;
    }

首先，我从代码中删除了Take部分，并使用FirstOrDefault始终获取跳过后的第一个元素。最后，Players元素只加载了一次，然后我使用了具有更易读代码的类的属性。

在List中跳过并获取方法

2 个答案: