Question

相关：Create a Lambda Expression With 3 conditions

请考虑此准则：

from a in myTbl
where a.Address.Contains(strToCheck)
select a

如何将其转换为表达式树并使用表达式编写上述代码？主要问题是将a.Address.Contains(strToCheck)转换为Expression Tree。

修改1）地址是 string 字段，strToCheck是 string

由于

Answer 1

a.Address.Contains(strToCheck)代表a.Address 实例上string.Contains 实例方法的调用 {{ 1}} 参数。

构建相应表达式的最简单方法是使用以下Expression.Call overload：

strToCheck

像这样（使用链接问题中的术语）：

public static MethodCallExpression Call(
    Expression instance,
    string methodName,
    Type[] typeArguments,
    params Expression[] arguments
)

Answer 2

您没有指定myTbl的类型，
所以我只使用一个对象列表创建了一个简单的解决方案。

using System;
using System.Linq;
using System.Linq.Expressions;
using System.Collections.Generic;

namespace Test
{
    class Program
    {
        static void Main(string[] args) {
            var adresses = FilterByAddress("Address", new List<Person> { new Person { Address = "Address1" }, new Person { Address = "AAAAAA" } });
        }

        public static IEnumerable<Person> FilterByAddress(string strToCheck, List<Person> list) {
            var listParam = Expression.Parameter(typeof(IEnumerable<Person>), "list");
            Expression<Func<Person, bool>> contains = a => a.Address.Contains(strToCheck);
            var select = typeof(Enumerable).GetMethods().Single(m => m.Name.Equals("Where") && m.GetParameters()[1].ParameterType.GetGenericArguments().Length == 2);
            var genericMethod = select.MakeGenericMethod(new[] { typeof(Person) });
            var call = Expression.Call(null, genericMethod, new Expression[] { listParam, contains });
            var lambda = Expression.Lambda<Func<IEnumerable<Person>, IEnumerable<Person>>>(call, new[] { listParam });

            return lambda.Compile().Invoke(list);
        }
    }

    public class Person
    {
        public string Address { get; set; }
    }
}

如果您想按谓词使用过滤器，可以传递Expresssion<Func<Person, bool>>作为参数（一行）

    static void Main(string[] args) {
        var strToCheck = "Address";
        var list = new List<Person> { new Person { Address = "Address1" }, new Person { Address = "AAAAAA" } };
        var adresses = FilterByAddress(list, p => p.Address.Contains(strToCheck));
    }

    public static IEnumerable<Person> FilterByAddress(List<Person> list, Expression<Func<Person, bool>> predicateEx) {
        var listParam = Expression.Parameter(typeof(IEnumerable<Person>), "list");
        var select = typeof(Enumerable).GetMethods().Single(m => m.Name.Equals("Where") && m.GetParameters()[1].ParameterType.GetGenericArguments().Length == 2);
        var genericMethod = select.MakeGenericMethod(new[] { typeof(Person) });
        var call = Expression.Call(null, genericMethod, new Expression[] { listParam, predicateEx });
        var lambda = Expression.Lambda<Func<IEnumerable<Person>, IEnumerable<Person>>>(call, new[] { listParam });

        return lambda.Compile().Invoke(list);
    }

如果你有一个跨越多行的非常复杂的谓词（表达式树可以从一行lambda中计算），你可以使用一个技巧从谓词Func中构造一个表达式树，如下所示：

    static void Main(string[] args) {
        var strToCheck = "Address";
        Func<Person, bool> predicate = p => {
            return p.Address.Contains(strToCheck);
        };

        var list = new List<Person> { new Person { Address = "Address1" }, new Person { Address = "AAAAAA" } };
        var adresses = FilterByAddress(list, predicate);
    }

    public static IEnumerable<Person> FilterByAddress(List<Person> list, Func<Person, bool> predicate) {
        var listParam = Expression.Parameter(typeof(IEnumerable<Person>), "list");
        Expression<Func<Person, bool>> predicateEx = p => predicate(p);
        var select = typeof(Enumerable).GetMethods().Single(m => m.Name.Equals("Where") && m.GetParameters()[1].ParameterType.GetGenericArguments().Length == 2);
        var genericMethod = select.MakeGenericMethod(new[] { typeof(Person) });
        var call = Expression.Call(null, genericMethod, new Expression[] { listParam, predicateEx });
        var lambda = Expression.Lambda<Func<IEnumerable<Person>, IEnumerable<Person>>>(call, new[] { listParam });

        return lambda.Compile().Invoke(list);
    }

使用通用方法按谓词过滤列表

    static void Main(string[] args) {
        var strToCheck = "Address";
        Func<Person, bool> predicate = p => {
            return p.Address.Contains(strToCheck);
        };

        var list = new List<Person> { new Person { Address = "Address1" }, new Person { Address = "AAAAAA" } };
        var adresses = FilterBy<Person>(list, predicate);
    }

    public static IEnumerable<T> FilterBy<T>(List<T> list, Func<T, bool> predicate) {
        var listParam = Expression.Parameter(typeof(IEnumerable<T>), "list");
        Expression<Func<T, bool>> predicateEx = p => predicate(p);
        var select = typeof(Enumerable).GetMethods().Single(m => m.Name.Equals("Where") && m.GetParameters()[1].ParameterType.GetGenericArguments().Length == 2);
        var genericMethod = select.MakeGenericMethod(new[] { typeof(T) });
        var call = Expression.Call(null, genericMethod, new Expression[] { listParam, predicateEx });
        var lambda = Expression.Lambda<Func<IEnumerable<T>, IEnumerable<T>>>(call, new[] { listParam });

        return lambda.Compile().Invoke(list);
    }
}

转换包含到表达式树

2 个答案: