我的弹性搜索数据类似于
{
"took": 12,
"timed_out": false,
"_shards": {
"total": 5,
"successful": 5,
"failed": 0
},
"hits": {
"total": 2,
"max_score": 1,
"hits": [
{
"_index": "eswar",
"_type": "azure",
"_id": "AV6y005oafdLlkt7Fe-R",
"_score": 1,
"_source": {
"costs": [
{
"cost": 3.6,
"endDate": "2017-02-15T00:00:00+00:00",
"startDate": "2017-02-14T00:00:00+00:00"
},
{
"cost": 2,
"endDate": "2017-02-14T00:00:00+00:00",
"startDate": "2017-02-13T00:00:00+00:00"
}
],
"externalUUID": "/subscriptions/9ee6993f-a036-4118-9eab-c66d9fda1ef3/resourceGroups/VISTARAGATEWAYIMAGE/providers/Microsoft.Compute/disks/VistaraGateway01_disk1_ec7798e17f934e6483ed5d2490e80d98",
"clientId": 154,
"region": "useast",
"cloudProviderId": 57063
}
},
{
"_index": "eswar",
"_type": "azure",
"_id": "AV6y00rmafdLlkt7Fe-Q",
"_score": 1,
"_source": {
"costs": [
{
"cost": 0,
"endDate": "2017-02-14T00:00:00+00:00",
"startDate": "2017-02-13T00:00:00+00:00"
},
{
"cost": 3,
"endDate": "2017-02-17T00:00:00+00:00",
"startDate": "2017-02-16T00:00:00+00:00"
}
],
"externalUUID": "/subscriptions/9ee6993f-a036-4118-9eab-c66d9fda1ef3/resourceGroups/vistaragatewayimage/providers/Microsoft.Compute/virtualMachines/VistaraGateway",
"clientId": 154,
"region": "eastus",
"cloudProviderId": 57063
}
}
]
}
}
我希望将cost.cost:3.6作为聚合结果,但我得到结果为5 如何在数组中过滤数据?
RangeQueryBuilder startDateRQB = QueryBuilders.rangeQuery("costs.startDate").gte("2017-02-14T00:00:00+00:00");
RangeQueryBuilder endDateRQB = QueryBuilders.rangeQuery("costs.endDate").lte("2017-02-15T00:00:00+00:00");
RegexpQueryBuilder deviceNameREQB= QueryBuilders.regexpQuery("region", "useast.*");
BoolQueryBuilder bQB=QueryBuilders.boolQuery().must(deviceNameREQB).must(startDateRQB).must(endDateRQB);
BoolQueryBuilder sQB=QueryBuilders.boolQuery().must(startDateRQB).must(endDateRQB);
SearchResponse response = client.prepareSearch(index).setQuery(bQB).addAggregation(AggregationBuilders.sum("Totalcost").field("costs.cost")).execute().actionGet();
Sum sum=response.getAggregations().get("Totalcost");
double cost=sum.getValue();
System.out.println(cost);
答案 0 :(得分:0)
我建议你将render
定义为嵌套对象。
然后,您将能够在内部数据中添加条件(嵌套文档)。
这种方法可以为您的查询提供广泛的可能性。
查看以下解决方案:
costs
让我解释一下每个聚合(按名称):
希望它有所帮助。