Question

我想实现脚本执行时间处理，但偶然发现了这个问题。如果我设计webdriver的脚本以下面的方式执行，它会成功返回一个变量，但它不会触发ScriptTimeoutException。有什么想法吗？我从webdriver's javadoc示例

采用了这个脚本

System.setProperty("webdriver.chrome.driver", "C:\\chromedriver.exe");
WebDriver driver = new ChromeDriver();
//---setting script timeout to 1ns to force ScriptTimeoutException
driver.manage().timeouts().setScriptTimeout(1, TimeUnit.NANOSECONDS);

//this script works fine, ScriptTimeoutException is triggered
String script1 = "window.setTimeout(arguments[arguments.length - 1], 500);";

//this script is able to pass his return variable back to Java, but doesn't triggers ScriptTimeoutException
String script2 = "var callback = arguments[arguments.length - 1];" +
        "var stringVar = 'abcd';" + 
        "callback(stringVar);";

while (true) {
    Instant beforeScript = Instant.now();
    //((JavascriptExecutor) driver).executeAsyncScript(script1);
    String result = (String) ((JavascriptExecutor) driver).executeAsyncScript(script2);
    System.out.println(result + " " + Duration.between(beforeScript, Instant.now()).toMillis());
}

Answer 1

好吧，在用selenium \ chromedriver开发人员搜索了一段时间并discussing之后，我发现我的脚本实际上并不是异步脚本。

将抛出ScriptTimeoutException的正确异步脚本将是这样的：

var callback = arguments[arguments.length - 1];
var stringVar = 'abcd';
setTimeout(()=>callback(stringVar), 100);

ChromeDriver的executeAsyncScript不会正确触发ScriptTimeoutException

1 个答案: