Question

if(isset($_GET['view_id']) && !empty($_GET['view_id'])){$id = $_GET['view_id'];

$stmt_edit = $DB_con->prepare('SELECT date_of_birth, phone_number,hostel_address, name_of_sponsors,phone_number_of_sponsors, gender,department, first_name, last_name, user_email, user_name, user_pass, FROM `100`WHERE user_id =:uid');
$stmt_edit->execute(array(':uid'=>$id));
$edit_row = $stmt_edit->fetch(PDO::FETCH_ASSOC);
extract($edit_row);}else{
header("Location: index.php");}

它向我展示了这些错误：

致命错误：未捕获的异常＆＃39; PDOException＆＃39; with message＆＃39; SQLSTATE [42000]：语法错误或访问冲突：1064 SQL语法中有错误;检查与您的MySQL服务器版本相对应的手册，以便在＆＃39; FROM 100附近使用正确的语法WHERE user_id =＆＃39; 19＆＃39;＆＃39;在第3行＆＃39;在第15行的C：\ wamp \ www \ registration \ admin \ levels \ 100level \ view.php

（！）PDOException：SQLSTATE [42000]：语法错误或访问冲突：1064 SQL语法中有错误;查看与您的MySQL服务器版本相对应的手册，以便在＆＃39; FROM 100附近使用正确的语法WHERE user_id =＆＃39; 19＆＃39;＆＃39;

Answer 1

在导致SQL语法错误的user_pass之后，您有更多“，”，您的查询必须是：

SELECT date_of_birth, phone_number,hostel_address, name_of_sponsors,phone_number_of_sponsors, gender,department, first_name, last_name, user_email, user_name, user_pass FROM `100` WHERE user_id =:uid

我想从数据库中查看特定的用户信息。但是我收到了这个错误

1 个答案: