Question

我正在使用Sidekiq尝试通过Firebase云消息传递（FCM）发送推送通知。 FCM需要使用它的服务器中的两件事：

指数退避
尊重500响应中的Retry-After标头

https://firebase.google.com/docs/cloud-messaging/http-server-ref#table4

我们可以免费获得Sidekiq的指数退避，但我不确定如何告诉它延迟重试，直到至少在标题中指定的时间。

我在下面有一个hacky解决方案，我在sleep之前创建了工作raise，但似乎重试逻辑应该存在于Sidekiq中。无论如何，我只是告诉Sidekiq有关Retry-After标题值的信息，以便它可以做正确的事情吗？

class SendPushNotification
  include Sidekiq::Worker
  sidekiq_options queue: :low

  def perform(user_id)
    notification = { body: 'hello world' }
    user = User.find(user_id)
    fcm_token = user.try(:fcm_token) || ENV['FCM_TOKEN']

    uri = URI('https://fcm.googleapis.com/fcm/send')

    http = Net::HTTP.start(uri.hostname, uri.port, use_ssl: true)

    req = Net::HTTP::Post.new(uri, 'Content-Type' => 'application/json',
                                   'Authorization' => "key=#{ENV['FCM_API_KEY']}")

    req.body = {
      badge: 0,                      # badge is removed when set to zero
      click_action: 'click',         # string
      collapse_key: 'Handshake',     # collapse multiple messages under this header
      content_available: true,       # wake inactive app
      data: nil,
      registration_ids: [fcm_token], # fcm device tokens
      notification: notification,
      mutable_content: true,         # iOS 10 feature
      priority: 'high',              # high or low (corresponds to 5 and 10 in apns)
      subtitle: nil,
      time_to_live: 2419200,         # max and default for FCM
      dry_run: false                # message is not sent when set to true
    }.to_json

    res =  http.request(req)

    case res
    when Net::HTTPOK
      true
    when Net::HTTPUnauthorized
      raise 'Unauthorized'
    when Net::HTTPBadRequest
      raise "BadRequest: #{res.body}"
    else
      if res.header['Retry-After']
        # this seems like a hacky solution
        sleep res.header['Retry-After']
      end
      raise 'Remote Server Error'
    end
  end
end

Answer 1

请勿使用Sidekiq的内置重试。安排一个与当前工作相同的新工作，在很多秒内运行。

 self.class.perform_in(res.header['Retry-After'].to_i, user_id)

如何使Sidekiq尊重Retry-After响应头？

1 个答案: