当不透明度为零时，下拉列表项仍可单击

Question

问题是当不透明度设置为零时，下拉按钮仍然可以点击。我将不透明度设置为零，因为需要褪色效果。有没有替代方法来获取动画，以及内容，是否被jquery隐藏？

您可以在示例中看到当我们将鼠标悬停在按钮下方时，光标变为指针并且元素是可点击的。

尝试这样做但从未工作

$(".btn").on('click', function(e) {
  e.stopPropagation();
  var child = $(this).siblings();

  if (!child.hasClass("visible")) {
    child.animate({
      'opacity': 1
    }, 1000);
    child.addClass("visible");
  } else {
    child.animate({
      'opacity': 0
    }, 1000);
    child.removeClass("visible");
  }
});

$(document).on('click', function(e) {
  $(".visible").animate({
    'opacity': 0
  }, 1000);
  $(".visible").removeClass("visible");
});

.btn {
  outline: none;
  border: none;
  padding: 10px 20px;
  cursor: pointer;
  background-color: #eee;
  color: #7b7b7b;
  width: 150px;
  box-shadow: 4px 4px 6px 0px rgba(0, 0, 0, .16);
  font-weight: bold;
  margin-bottom: 20px;
}

.dropdown {
  position: relative;
  display: inline;
}

.btn-dropdown {
  padding: 0px;
  margin: 0px;
  list-style: none;
  background-color: #fff;
  position: absolute;
  left: 0px;
  top: 30px;
  box-shadow: 4px 4px 6px 0px rgba(0, 0, 0, .16);
  min-width: 200px;
  border: 1px solid #ddd;
  text-align: initial;
  max-height: 210px;
  overflow: auto;
  opacity: 0;
  z-index: 100;
}

.btn-dropdown li {
  padding: 6px;
  margin: 0px;
  border-bottom: 1px solid #ddd;
  cursor: pointer;
}

.btn-dropdown li:hover {
  background-color: #ddd;
}

.btn-dropdown li:last-child {
  border-bottom: none;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="dropdown">
  <button class="btn first">Select something</button>
  <ul class="btn-dropdown">
    <li>First</li>
    <li>Second</li>
    <li>Third</li>
    <li>Fourth</li>
  </ul>
</div>

<div class="dropdown">
  <button class="btn first">Select something</button>
  <ul class="btn-dropdown">
    <li>Black</li>
    <li>Brown</li>
    <li>Red</li>
    <li>Orange</li>
  </ul>
</div>

Answer 1

问题是因为当您将opacity设置为0时，元素仍然在DOM中，并且仍然可以与之交互，尽管它们无法被看到 - 类似于{{1 }}

要解决此问题，您应该使用visibility: none。您还可以使用display: none和fadeToggle()的组合简化逻辑，如下所示：

fadeOut()

$(".btn").on('click', function(e) {
  e.stopPropagation();
  var $dropdown = $(this).siblings().fadeToggle(); // toggle this dropdown
  $('.dropdown .btn-dropdown').not($dropdown).fadeOut(); // hide other dropdowns
});

$(document).on('click', function(e) {
  $('.dropdown .btn-dropdown').fadeOut(); // hide all dropdowns
});

.btn {
  outline: none;
  border: none;
  padding: 10px 20px;
  cursor: pointer;
  background-color: #eee;
  color: #7b7b7b;
  width: 150px;
  box-shadow: 4px 4px 6px 0px rgba(0, 0, 0, .16);
  font-weight: bold;
  margin-bottom: 20px;
}

.dropdown {
  position: relative;
  display: inline;
}

.btn-dropdown {
  padding: 0px;
  margin: 0px;
  list-style: none;
  background-color: #fff;
  position: absolute;
  left: 0px;
  top: 30px;
  box-shadow: 4px 4px 6px 0px rgba(0, 0, 0, .16);
  min-width: 200px;
  border: 1px solid #ddd;
  text-align: initial;
  max-height: 210px;
  overflow: auto;
  display: none;
  z-index: 100;
}

.btn-dropdown li {
  padding: 6px;
  margin: 0px;
  border-bottom: 1px solid #ddd;
  cursor: pointer;
}

.btn-dropdown li:hover {
  background-color: #ddd;
}

.btn-dropdown li:last-child {
  border-bottom: none;
}