我有以下命令产生此输出
命令：
oozie job -info 0007218-170910003406158-oozie-oozi-W | grep job | awk '{print $3}' | cut -c1-23 | sed 's/job/application/'
输出：
application_1505017974932_23474 application_1505017974932_23478 application_1505017974932_23477 application_1505017974932_23473 application_1505017974932_23475 application_1505017974932_23471 application_1505017974932_23469 application_1505017974932_23476 application_1505017974932_23472 application_1505017974932_23470 application_1505017974932_23495 application_1505017974932_23497 application_1505017974932_23500 application_1505017974932_23501
我需要将这些输出行作为输入传递给下面的命令，同时将日志文件存储在/ tmp文件夹中
yarn logs -applicationId <applicationID> -Owner <userID> > /tmp/<applicationID>.txt
尝试使用for循环但面临挑战的单一语法自动执行此操作。有问题的当前for循环在
之下for appid in `oozie job -info 0007218-170910003406158-oozie-oozi-W | grep job | awk '{print $3}' | cut -c4-23 | sed 's/job/application/'`; do yarn logs -applicationId "${appid}" -Owner user9 > /tmp/ "${appid}"; done
目前正在收到如下错误
Invalid ApplicationId specified Invalid ApplicationId specified Invalid ApplicationId specified Invalid ApplicationId specified Invalid ApplicationId specified
如果我们没有将正确的applicationid指定为参数，通常我们会得到这个。