Question

total = 0
A1 = ["Big Mac", float(2.50), 50]
B1 = ["Large Fries", float(0.50), 200]
C1 = ["Vegetarian Burger", float(1.00), 20]

print(A1[0:2])
print(B1[0:2])
print(C1[0:2])

while True:
    choice = (input("What would you like?")).upper()
    quantity = float(input("How many would you like?"))

    if choice == "BIG MAC":
        if quantity > A1[2]:
            print("There is not enough stock!")
            pass
        else:
            total += A1[1]*quantity
            A1[2] -= quantity

    elif choice == "LARGE FRIES":
        if quantity > B1[2]:
            print("There is not enough stock!")
            pass
        else:
            total += B1[1]*quantity
            B1[2] -= quantity

    elif choice == "VEGETARIAN BURGER":
        if quantity > C1[2]:
            print("There is not enough stock!")
            pass
        else:
            total += C1[1]*quantity
            C1[2] -= quantity
    more_items = (input("Do you want to order more items?")).lower()
    if more_items == "yes":
        pass
    else:
        break

print("Thank you for ordering!\n"
      "Your total cost is:", total)

我正在尝试通过column = column >= (numberOfColumns - 1) ? 0 : ++column符号增加我的列变量，但现在已弃用。这个增量的最佳标志是什么？

我尝试了++和column++。虽然它在正常的if-else条件下工作，但我想通过内联条件实现它。

Answer 1

简单的增量怎么样？

column = column >= (numberOfColumns - 1) ? 0 : column + 1

在Swift 3.1中以inline条件递增运算符

1 个答案: