Question

我希望通过添加函数来提高代码的效率。 if语句中的任务实际上是相同的 - 只有变量才会发生变化。但是，我不知道如何根据用户对该功能的选择来更改列表。有谁知道这样做的方法？

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Answer 1

将您的项目列表转换为dict会有所帮助，并且可以减少必须声明所有if-elif -else语句

total = 0

item_dict = {
"BIG MAC": [float(2.50), 50],
"LARGE FRIES": [float(0.50), 200],
"VEGETARIAN BURGER": [float(1.00), 20]}

def order_adder(menu_item, quantity, total):
    try:
        if item_dict[menu_item][1] - quantity < 0:
            print("There is not enough stock!")
        else:
            item_dict[menu_item][1] = item_dict[menu_item][1] - quantity
            total += item_dict[menu_item][0]*quantity
    except(KeyError):
        print("We don't sell that item")
    return total

while True:
    choice = (input("What would you like?")).upper()
    quantity = float(input("How many would you like?"))

    total = order_adder(choice, quantity, total)

    more_items = (input("Do you want to order more items?")).lower()
    if more_items == "yes":
        pass
    else:
        break

print("Thank you for ordering!\n"
      "Your total cost is:", total)

Answer 2

您必须使用通用功能创建一个函数，并为每种情况传递不同的参数。

功能：

def processOrder(quantity, stock, total):
    if quantity > stock[2]:
        print("There is not enough stock!")
        pass
    else:
        total += stock[1] * quantity
        stock[2] -= quantity

整个计划：

def processOrder(quantity, stock, total):
    if quantity > stock[2]:
        print("There is not enough stock!")
        pass
    else:
        total += stock[1] * quantity
        stock[2] -= quantity

total = 0
A1 = ["Big Mac", float(2.50), 50]
B1 = ["Large Fries", float(0.50), 200]
C1 = ["Vegetarian Burger", float(1.00), 20]

print(A1[0:2])
print(B1[0:2])
print(C1[0:2])

while True:
    choice = (input("What would you like?")).upper()
    quantity = float(input("How many would you like?"))

      more_items = (input("Do you want to order more items?")).lower()
    if more_items == "yes":
        pass
    else:
        break

print("Thank you for ordering!\n"
      "Your total cost is:", total)
 if choice == "BIG MAC":
        processOrder(quantity, A1, total)

    elif choice == "LARGE FRIES":
        processOrder(quantity, B1, total)

    elif choice == "VEGETARIAN BURGER":
        processOrder(quantity, C1, total)

Answer 3

调整DobromirM的回答：

total = 0
def processOrder(quantity, stock):
    global total
    if quantity > stock[2]:
        print(quantity, stock[1])
        print("There is not enough stock!")
        pass
    else:
        total += stock[1] * quantity
        stock[2] -= quantity

A1 = ["Big Mac", float(2.50), 50]
B1 = ["Large Fries", float(0.50), 200]
C1 = ["Vegetarian Burger", float(1.00), 20]

print(A1[0:2])
print(B1[0:2])
print(C1[0:2])

while True:
    choice = (input("What would you like?")).upper()
    quantity = float(input("How many would you like?"))
    if choice == "BIG MAC":
        processOrder(quantity, A1)
    elif choice == "LARGE FRIES":
        processOrder(quantity, B1)
    elif choice == "VEGETARIAN BURGER":
        processOrder(quantity, C1)
    more_items = (input("Do you want to order more items?")).lower()
    if more_items == "yes":
        pass
    else:
        break

print("Thank you for ordering!\nYour total cost is:", total)

Answer 4

如果您将订单选项放入2D列表中，则可以更轻松地对订单进行索引。

def process_choice(quantity,stock,price,total):
    if quantity > stock:
        print("There is not enough stock!")
        pass
    else:
        total += price*quantity
        stock -= quantity
    return total, stock        


total = 0    
A = [["Big Mac", float(2.50), 50],["Large Fries", float(0.50), 200],["Vegetarian Burger", float(1.00), 20]]

print(A[0])
print(A[1])
print(A[2])

while True:
    choice = (input("What would you like?")).upper()
    quantity = float(input("How many would you like?"))

    choices = [A[0][0].upper(),A[1][0].upper(),A[2][0].upper()]
    idx = choices.index(choice)

    total, A[idx][2] = process_choice(quantity,A[idx][2],A[idx][1],total)

    more_items = (input("Do you want to order more items?")).lower()
    if more_items == "yes":
        pass
    else:
        break

print("Thank you for ordering!")
print("Your total cost is:", total)

如何将不同的变量集成到一个函数中？

4 个答案: