Question

我几天来一直在研究用Python类编程简介这个问题。目标是创建一个程序，从用户输入的单词列表中生成随机电影标题。输出应该如下所示：

Please enter a list of words: ["Space", "Show", "Adventure", "Story", 
"Love", "Wild", "Life"]

Please enter a number of movies you'd like to generate: 3

输出：

欢迎来到Randoplex！目前正在播放的电影是：

冒险生活空间

展示爱情故事

野生太空生活

我已经能够生成随机标题，但无论如何都无法根据用户输入的数字生成不同的标题。这是我得到的最接近的：

import random

def random_movies(word_list = eval(input("Please enter a list of words:"))):

    for word in word_list:
        titles = ' '.join(random.choice(word_list) for i in range(3))
    return titles

def repeat():

  titles = random_movies()
  movie_num = eval(input("Please enter the number of movies you'd like to  generate:"))

 for i in range(movie_num):
    random_movies()
    print(titles)

titles1 = repeat()
print("Welcome to Randoplex! Currently playing movies are:")
print()
print(titles1)

这允许我为用户输入的值movie_num打印相同的随机标题。但是，我无法弄清楚如何创建多个不同的随机电影片头。我尝试过以多种不同的方式使用range()功能，并在互联网上寻求建议。我真的不知道还有什么可以尝试，任何帮助将不胜感激。值得一提的是，我的班级非常基础，我们还没有被引入＆＃34;而＃34;循环，我不认为我被允许使用它们因此。先感谢您。

Answer 1

您的功能正常工作，但在您的for循环中，您打印的电影标题，您忘记将变量重新分配给新生成的电影标题。生成了不同的标题，但只打印了第一个标题。

import random

def random_movie(word_list = eval(input("Please enter a list of words:"))):
    for word in word_list:
        title = ' '.join(random.choice(word_list) for i in range(3))
        return title

def repeat():
    movie_num = eval(input("Please enter the number of movies you'd like to  generate:"))
    for i in range(movie_num):
        title = random_movie()
        print(title)

print("Welcome to Randoplex! Currently playing movies are: ")
print()
repeat()

Answer 2

这是否符合您的要求？

import random

def random_movies(word_list):
    for word in word_list:
        titles = ' '.join(random.choice(word_list.split()) for i in range(3))
        return titles

word_list = input("Please enter a list of words:")
movie_num = int(input("Please enter the number of movies you'd like to  generate:"))

print("Welcome to Randoplex! Currently playing movies are:")

for i in range(movie_num):
    print(random_movies(word_list))

Answer 3

获得类似结果的另一种方式。

import itertools
import random
noofmovies = 3
movies =  ["Space", "Show", "Adventure", "Story", "Love", "Wild", "Life"]
newmovies = []
def random_movie(movies):

    for r in range(2,len(movies)):
        for elem in itertools.combinations(movies, r):
            newmovies.append(" ".join(elem))


def repeat():
    random.shuffle(newmovies)
    for elem in newmovies[0:noofmovies]:
        print (elem)


print("Welcome to Randoplex! Currently playing movies are: ")
random_movie(movies)
repeat()

输出：

Show Adventure Story Wild Life
Story Wild Life
Show Adventure Story Love Wild Life

如果您只想连接3个电影名称，请删除范围内的r（2，len（电影））：循环并将硬编码转换为3

在函数Python 3中重复循环

3 个答案: