Question

我正在尝试清理一些按时间顺序排列的数据，以删除重复的时间顺序数据。

示例表：

+--------+------------+----------------+
| emp_id | department | effective_date |
+--------+------------+----------------+
|      1 | 50         | 2015-04-01     |
|      1 | 50         | 2015-05-22     |
|      1 | null       | 2015-07-04     |
|      1 | null       | 2015-07-24     |
|      1 | null       | 2015-07-30     |
|      1 | 50         | 2015-09-07     |
|      1 | 50         | 2016-01-16     |
|      1 | null       | 2016-04-23     |
|      2 | 60         | 2015-01-20     |
|      2 | 60         | 2015-11-22     |
|      2 | 60         | 2016-07-20     |
|      3 | 50         | 2015-04-02     |
|      3 | 50         | 2015-07-15     |
|      3 | 60         | 2016-01-25     |
+--------+------------+----------------+

如您所见，具有相同department的同一个人可能拥有相同的部门，但可能有多个effective_date。我想用查询来清理它，只有每个部门更改的第一个日期。但是，我不想删除有人从department 50转到null然后再回到50的实例，因为这些是实际的位置变化。< / p>

示例输出：

+--------+------------+----------------+
| emp_id | department | effective_date |
+--------+------------+----------------+
|      1 | 50         | 2015-04-01     |
|      1 | null       | 2015-07-04     |
|      1 | 50         | 2015-09-07     |
|      1 | null       | 2016-04-23     |
|      2 | 60         | 2015-01-20     |
|      3 | 50         | 2015-04-02     |
|      3 | 60         | 2016-01-25     |
+--------+------------+----------------+

我怎样才能做到这一点？

Answer 1

我的解决方案是

DECLARE @myTable  TABLE (emp_id INT, department INT, effective_date DATE);

INSERT INTO @myTable  VALUES
(1, 50  , '2015-04-01'),
(1, 50  , '2015-05-22'),
(1, null, '2015-07-04'),
(1, null, '2015-07-24'),
(1, null, '2015-07-30'),
(1, 50  , '2015-09-07'),
(1, 50  , '2016-01-16'),
(1, null, '2016-04-23'),
(2, 60  , '2015-01-20'),
(2, 60  , '2015-11-22'),
(2, 60  , '2016-07-20'),
(3, 50  , '2015-04-02'),
(3, 50  , '2015-07-15'),
(3, 60  , '2016-01-25')


;WITH T AS (
    SELECT *, 
        RN = ROW_NUMBER() OVER(PARTITION BY emp_id ORDER BY effective_date)
    FROM @myTable 
)
SELECT T1.emp_id, T1.department, T1.effective_date 
FROM 
    T T1 
    LEFT JOIN T T2 ON T1.emp_id = T2.emp_id AND T1.RN -1 = T2.RN 
WHERE (CASE WHEN ISNULL(T1.department,'') = ISNULL(T2.department,'') THEN 1 ELSE 0 END) = 0
ORDER BY T1.emp_id, T1.RN

结果：

emp_id      department  effective_date
----------- ----------- --------------
1           50          2015-04-01
1           NULL        2015-07-04
1           50          2015-09-07
1           NULL        2016-04-23
2           60          2015-01-20
3           50          2015-04-02
3           60          2016-01-25

(7 row(s) affected)

删除重复值：

;WITH T AS (
    SELECT *, 
        RN = ROW_NUMBER() OVER(PARTITION BY emp_id ORDER BY effective_date)
    FROM @myTable 
)
DELETE T1
FROM 
    T T1 
    LEFT JOIN T T2 ON T1.emp_id = T2.emp_id AND T1.RN -1 = T2.RN 
WHERE ( CASE 
        WHEN ISNULL(T1.department,'') <> ISNULL(T2.department,'') THEN 1 
        ELSE 0 END ) = 0

where子句

的替代方案

WHERE ( CASE WHEN T1.department <> T2.department 
            OR (T1.department IS NULL AND T2.department IS NOT NULL) 
            OR (T2.department IS NULL AND T1.department IS NOT NULL) 
        THEN 1 ELSE 0 END ) = 0

Answer 2

这比预期更难：

declare @temp as table (emp_id int, department int,effective_date date)


insert into @temp
values
    (1,50,'2015-04-01')
,   (1,50,'2015-05-22')
,   (1, null       ,'2015-07-04')
,   (1, null       ,'2015-07-24')
,   (1, null       ,'2015-07-30')
,   (1,50,'2015-09-07')
,   (1,50,'2016-01-16')
,   (1, null       ,'2016-04-23')
,   (2,60,'2015-01-20')
,   (2,60,'2015-11-22')
,   (2,60,'2016-07-20')
,   (3,50,'2015-04-02')
,   (3,50,'2015-07-15')
,   (3,60,'2016-01-25')


;with cte as
(
--Please not I am changing null to -1 for comparison    
select emp_id,isnull(department,-1) department,effective_date
  ,row_number() over (partition by emp_id order by effective_date) rn 
from @temp
)
,cte2 as
(
--Compare to next record
select cte.*
    ,ctelast.emp_id cte2Emp
    ,ctelast.department cte2dept
    ,ctelast.effective_date cte2ED
    ,isSame = case when cte.department=ctelast.department then 1 else 0 end
from cte
    join cte ctelast
        on cte.emp_id=ctelast.emp_id and cte.rn = ctelast.rn-1 
)

/*
Result of above:
emp_id  department  effective_date  rn  cte2Emp cte2dept    cte2ED  isSame
1   50  2015-04-01  1   1   50  2015-05-22  1
1   50  2015-05-22  2   1   -1  2015-07-04  0
1   -1  2015-07-04  3   1   -1  2015-07-24  1
1   -1  2015-07-24  4   1   -1  2015-07-30  1
1   -1  2015-07-30  5   1   50  2015-09-07  0
1   50  2015-09-07  6   1   50  2016-01-16  1
1   50  2016-01-16  7   1   -1  2016-04-23  0
2   60  2015-01-20  1   2   60  2015-11-22  1
2   60  2015-11-22  2   2   60  2016-07-20  1
3   50  2015-04-02  1   3   50  2015-07-15  1
3   50  2015-07-15  2   3   60  2016-01-25  0
*/

--Now you want both the first record and then any changes


select emp_id,department,effective_date from cte2 where rn=1
union all
select cte2emp,cte2dept,cte2.cte2ED from cte2 where isSame=0
order by 1,3

/*
result:
emp_id  department  effective_date
1   50  2015-04-01
1   -1  2015-07-04
1   50  2015-09-07
1   -1  2016-04-23
2   60  2015-01-20
3   50  2015-04-02
3   60  2016-01-25
*/

清理重复的时间顺序值

2 个答案: