Question

我正在使用序列化程序组件的symfony，并且有一个序列化和对象到JSON格式的示例，下一步：

    $encoders = array(new XmlEncoder(), new JsonEncoder());
    $normalizers = array(new ObjectNormalizer());

    $person = new \AppBundle\Entity\Person();
    $person->setName('foo');
    $person->setAge(99);
    $person->setSportsman(false);

    // return new JsonResponse($person); // empty

    $serializer = new Serializer($normalizers, $encoders);

    /**
     * 1 param - object to be serialized
     * 2 param - proper encoder, in this case JsonEncoder
     * @var [type]
     */
    $jsonContent = $serializer->serialize($person, 'json');

    return new Response($jsonContent);

上面的示例返回如下内容：

{"id":null,"age":99,"name":"foo","sportsman":false}

但我想知道如何做同样的，而不是CSV JSON

Answer 1

自Symfony 3.2以来添加了CSV和YAML编码器

// instantiation, when using it as a component
use Symfony\Component\Serializer\Serializer;
use Symfony\Component\Serializer\Encoder\CsvEncoder;
use Symfony\Component\Serializer\Normalizer\ObjectNormalizer;

$serializer = new Serializer([new ObjectNormalizer()], [new CsvEncoder()]);

// instantiation, when using it inside the Symfony framework
$serializer = $container->get('serializer');

// encoding contents in CSV format
$serializer->encode($data, 'csv');

// decoding CSV contents
$data = $serializer->decode(file_get_contents('data.csv'), 'csv');

您可以在那里找到更多信息：https://symfony.com/blog/new-in-symfony-3-2-csv-and-yaml-encoders-for-serializer

如何用Symfony编码Csv

1 个答案: