Question

我写了一个脚本，得到＆amp;从其他服务器备份文件，它的工作原理从控制台执行时，但从cron执行时失败。

这是我的剧本。

#!/bin/bash

# working directory
dir_work="somedir/work"

# backup directory
dir_bkup="somedir/bkup"

# db2 setting
. $HOME/sqllib/db2profile

# Get file by using SCP
getFilebyScp(){
    scp -i KEY -p user@10.0.0.1:"$download_file" "$dir_work"
RC=$?
    if [ $RC -ne 0 ]; then
      { echo 'Cannot get the file...'; exit $RC; }
    fi
}

# Processing Start
echo 'START'

# DB Connection
db2 connect to DATABASE user USERNAME using PASSWORD || { echo "database connection failed."; exit 1; }

# assign file_information to an array
file_info="($(db2 -x -t "select status, file_path from SOME_TABLE \
                where id = 999 \
                and status = 2 \
                and entry_id = (select max(entry_id) from SOME_TABLE where id = 999)"))"

download_file="${file_info[1]}"

# check the status of file 
if [ "${file_info[0]}" -eq 2 ]; then
  getFilebyScp
elif [ "${file_info[0]}" -eq 1 ]; then
  { echo 'Skip the process because output if the file is not finished yet.'; exit 1; }
else
  { echo 'Skip the process because some error happen in output file.'; exit 1; }
fi

new_file="$(basename "${download_file// /_}")"
mv -f "$download_file" "$new_file"

bkup_file=${new_file%%.csv}'_'$(date +%Y%m%d%H%M%S).csv
mv -f "${new_file}" "${dir_bkup}"/"${bkup_file}" || { 'Backup failed...'; exit 1; }

echo 'END'

和crontab就是这样。

15 17 * * * /bin/bash -l /somedir/otherdir/myscript.sh > crontab.log

那有什么问题？

附加说明

脚本和crontab帐户的用户帐户相同。
DB2实例名称为db2inst1
操作系统是RHEL（版本未知）。

[解决]

我发现$()命令作为子shell执行，因此子shell中没有初始连接。所以我修改了下面的脚本。＃！/斌/庆典

# working directory
dir_work="somedir/work"

# backup directory
dir_bkup="somedir/bkup"

# db2 setting
. $HOME/sqllib/db2profile

# Get file by using SCP
getFilebyScp(){
    scp -i KEY -p user@10.0.0.1:"$download_file" "$dir_work"
RC=$?
    if [ $RC -ne 0 ]; then
      { echo 'Cannot get the file...'; exit $RC; }
    fi
}

# Processing Start
echo 'START'

# DB Connection
db2 connect to DATABASE user USERNAME using PASSWORD || { echo "database connection failed."; exit 1; }

# assign file_informations
db2 -txf "/somedir/otherdir/status.sql" > "$dir_work"/status
db2 -txf "/somedir/otherdir/path.sql" > "$dir_work"/path
original_file_status=$(cat "$dir_work/status")
original_file_path=$(cat "$dir_work/path")

download_file="${original_file_path}"

# check the status of file 
if [ "$original_file_status" -eq 2 ]; then
  getFilebyScp
elif [ "$original_file_status" -eq 1 ]; then
  { echo 'Skip the process because output if the file is not finished yet.'; exit 1; }
else
  { echo 'Skip the process because some error happen in output file.'; exit 1; }
fi

new_file="$(basename "${download_file// /_}")"
mv -f "$download_file" "$new_file"

bkup_file=${new_file%%.csv}'_'$(date +%Y%m%d%H%M%S).csv
mv -f "${new_file}" "${dir_bkup}"/"${bkup_file}" || { 'Backup failed...'; exit 1; }

echo 'END'

我将数组中的元素拆分为两个变量，并使用两个SQL文件分配每个变量。

感谢您的评论！

Answer 1

$()命令作为子外壳程序执行，因此初始连接在子外壳程序中不可用。所以我修复了如下脚本。

#!/bin/bash

# working directory
dir_work="somedir/work"

# backup directory
dir_bkup="somedir/bkup"

# db2 setting
. $HOME/sqllib/db2profile

# Get file by using SCP
getFilebyScp(){
    scp -i KEY -p user@10.0.0.1:"$download_file" "$dir_work"
RC=$?
    if [ $RC -ne 0 ]; then
      { echo 'Cannot get the file...'; exit $RC; }
    fi
}

# Processing Start
echo 'START'

# DB Connection
db2 connect to DATABASE user USERNAME using PASSWORD || { echo "database connection failed."; exit 1; }

# assign file_informations
db2 -txf "/somedir/otherdir/status.sql" > "$dir_work"/status
db2 -txf "/somedir/otherdir/path.sql" > "$dir_work"/path
original_file_status=$(cat "$dir_work/status")
original_file_path=$(cat "$dir_work/path")

download_file="${original_file_path}"

# check the status of file 
if [ "$original_file_status" -eq 2 ]; then
  getFilebyScp
elif [ "$original_file_status" -eq 1 ]; then
  { echo 'Skip the process because output if the file is not finished yet.'; exit 1; }
else
  { echo 'Skip the process because some error happens in the output file.'; exit 1; }
fi

new_file="$(basename "${download_file// /_}")"
mv -f "$download_file" "$new_file"

bkup_file=${new_file%%.csv}'_'$(date +%Y%m%d%H%M%S).csv
mv -f "${new_file}" "${dir_bkup}"/"${bkup_file}" || { 'Backup failed...'; exit 1; }

echo 'END'

我将数组中的元素分为两个变量，并使用两个SQL文件为每个变量分配了变量。

从cron执行时，shell脚本中的数据库连接失败

1 个答案: