Question

鉴于此表：

订单
custName描述to_char（价格）
一个desa $ 14
B desb $ 14
C desc $ 21
D desd $ 65
E dese $ 21
F desf $ 78
G desg $ 14
H desh $ 21

我试图显示价格最高的整行，在这种情况下为14美元和21美元

我认为需要有一个子查询。所以我从这开始：

select max(count(price))  
from orders  
group by price

给了我3。

经过一段时间后，我认为这没有用。我相信我需要值14和21而不是计数，所以我可以把它放在where子句中。但是我发现了如何显示它。有什么帮助吗？

更新：所以我让它从这个

查询14和21

    select price
    from orders
    group by price
    having (count(price)) in
    (select max(count(price))
    from orders
    group by price)

但是我需要它来显示我得到错误的custname和description列：

select custname, description, price
from orders
group by price
having (count(price)) in
(select max(count(price))
from orders
group by price)

SQL Error: ORA-00979: not a GROUP BY expression

对此有何帮助？

Answer 1

我猜你很亲密。由于HAVING在GROUPed结果集上运行，请尝试

HAVING COUNT(price) IN

或

HAVING COUNT(price) =

替换当前行。

Answer 2

由于您将问题标记为oracle，因此您可以使用windowing functions在同一查询中获取聚合和详细数据。

SELECT   COUNT (price) OVER (PARTITION BY price) count_at_this_price, 
         o.* 
from orders o 
order by 1 desc

Answer 3

select employee, count(employee)
from work
group by employee
having count(employee) =
( select max(cnt) from
( select employee, count(employee cnt
from work
group by employee
)
);

Reference

Answer 4

您可以尝试类似

的内容

select * from orders where price in (select top 2 price from orders group by price order by price desc)

我不确定在Oracle中限制结果，在SQL Server中是顶级的，也许你应该使用限制。

在SQL中查找列中出现的最大次数

4 个答案: