Question

我目前正试图理解如何使用连接表的SQL结果在现有循环中循环结果。

首先，这是我目前的代码：

<?php
include('OrderCore/connect-db.php');
$POIds = array();
if ($result = $mysqli->query("SELECT ProductionOrderID FROM ProductionOrder" ) ) {
    while ($row = $result->fetch_object()) {
        $POIds[] = $row->ProductionOrderID;
    }
}
foreach ( $POIds as $index => $OrderId ) {
    if ( $result = $mysqli->query("
    SELECT * 
    FROM ProductionOrder AS p
    LEFT JOIN ProductionOrderStatus AS s ON ( p.ProductionOrderID = s.ProductionOrderStatusID ) 
    LEFT JOIN NotGood AS n ON ( p.ProductionOrderID = n.NGID ) 
    LEFT JOIN BatchOrder AS b ON ( p.ProductionOrderID = b.ProductionOrderID)
    LEFT JOIN Brand AS bd ON ( p.ProductionOrderID = bd.BrandID ) 
    LEFT JOIN CustomerOrder AS co ON ( p.ProductionOrderID = co.COID ) 
    LEFT JOIN Customer AS c ON ( p.ProductionOrderID = c.CustomerID ) 
    LEFT JOIN CustomerOrderStatus AS cos ON ( p.ProductionOrderID = cos.COStatusID )
    WHERE p.ProductionOrderID='$OrderId'") ) {
        while( $row = $result->fetch_object() ) {
            print "<h1>Order: $OrderId</h1>";
            print "<table class='table table-striped'>";
            print "<tr> <th>PO ID</th> <th>PO #</th> <th>Order Quantity</th> <th>Balance Left</th> <th>Production Date</th> <th>Production Order Status</th> <th>Not Good ID</th> </tr>";
            print "<td>" . $row->ProductionOrderID . "</td>";
            print "<td>" . $row->PONum . "</td>";
            print "<td>" . $row->OrderQTY . "</td>";
            print "<td>" . $row->BalLeftNum . "</td>";
            print "<td>" . $row->ProductionDate . "</td>";
            print "<td>" . $row->ProductionOrderStatusID . "</td>";
            print "<td>" . $row->NGID . "</td>";
            print "</tr>";
            print "</table>";
            //BatchOrder
            print "<table class='table table-striped'>";
            print "<tr> <th>Batch ID</th> <th>Brand Name</th> <th>Batch Quantity</th> <th>Availability Date</th> <th>Remaining Balance</th> <th>Production Order ID</th> </tr>";
            print "<td>" . $row->BatchID . "</td>";
            print "<td>" . $row->BrandID . "</td>";
            print "<td>" . $row->BatchQTY . "</td>";
            print "<td>" . $row->AvailDate . "</td>";
            print "<td>" . $row->RemainBal . "</td>";
            print "<td>" . $row->ProductionOrderID . "</td>";
            print "</tr>";
            print "</table>";
            //CustomerOrder
            print "<table class='table table-striped'>";
            print "<tr> <th>Customer ID</th> <th>Customer Name</th> <th>Invoice Quantity</th> <th>Invoice #</th> <th>Shipping Date</th> <th>Batch ID</th> <th>CO Status</th> </tr>";
            print "<td>" . $row->COID . "</td>";
            print "<td>" . $row->CustomerID . "</td>";
            print "<td>" . $row->InvoiceQTY . "</td>";
            print "<td>" . $row->InvoiceNum . "</td>";
            print "<td>" . $row->ShipDate . "</td>";
            print "<td>" . $row->BatchID . "</td>";
            print "<td>" . $row->COStatusID . "</td>";
            print "</tr>";
            print "</table>";
        }
    }
    else
    {
        print "No results to display!";
    }
}
$mysqli->close();
?>

此代码目前产生此结果：https://i.imgur.com/y7uh6nk.png。这几乎是正确的预期行为......每个ProductionOrderID都应生成一个包含2个子表的新表：BatchOrder和CustomerOrder。但它目前只为每个子表显示1个结果。

因此，为了澄清，用户可以创建任意数量的ProductionOrder（因此foreach循环遍历数组）。每个ProductionOrder都可以包含：零，一个或多个BatchOrder，每个BatchOrder可以包含：零，一个或多个CustomerOrder s。

当前问题： 根据上面的屏幕截图链接，它每BatchOrder只显示1 CustomerOrder和1 ProductionOrder。我的示例数据包含ProductionOrderID=1的多个批量订单，但它们不会显示。

我不确定问题是部分PHP还是部分SQL相关。我是两种语言的新手，但我怀疑LEFT JOIN是不正确的。但是，它是唯一一种（当前）正确显示每个ProductionOrder并且每个BO和CO的方法...只是不是全部。我还怀疑我需要在现有的while循环中执行另一个循环但是我不确定正确的方法，因为我当前的尝试都没有成功。

详细信息 以下是包含示例数据的数据库SQL的副本：https://pastebin.com/A3rt8kX4

我的ERD也显示了预期的行为：https://i.imgur.com/idVR5ev.png

任何帮助不仅可以帮助解决当前的问题，还可以帮助我理解为什么它的错误是绝对赞赏的。

编辑：1 我修复了在SELECT语句中加入的键，但现在只看到一个PO：

https://i.imgur.com/doRmS0c.png

SELECT * 
FROM ProductionOrder AS p
INNER JOIN ProductionOrderStatus AS s ON ( p.ProductionOrderID = s.ProductionOrderID ) 
INNER JOIN NotGood AS n ON ( p.ProductionOrderID = n.ProductionOrderID ) 
INNER JOIN BatchOrder AS b ON ( p.ProductionOrderID = b.ProductionOrderID )
INNER JOIN Brand AS bd ON ( b.BatchID = bd.BatchID ) 
INNER JOIN CustomerOrder AS co ON ( b.BatchID = co.BatchID ) 
INNER JOIN Customer AS c ON ( co.COID = c.COID ) 
INNER JOIN CustomerOrderStatus AS cos ON ( co.COID = cos.COID )
WHERE p.ProductionOrderID='$OrderId'") ) {

Answer 1

您需要将主键加入相应的外键，例如：

LEFT JOIN ProductionOrderStatus AS s ON ( p.ProductionOrderID = s.ProductionOrderStatusID )

应该是

LEFT JOIN ProductionOrderStatus AS s ON ( p.ProductionOrderID = s.ProductionOrderID )

您在大多数联接中遇到同样的问题。

如何在现有的foreach内部循环连接SQL表

1 个答案: