Question

这是我的第一个数据框的头部，A1：

            K37L  K37M  K37N  K37P  K37Q  K37R  K37S  K37T  K37U  K37V  ...   \
1997-01-01  79.8  80.4  72.8  36.7   0.0  90.0  96.9  92.2  79.8  93.7  ...    
1997-02-01  79.1  81.7  73.6  36.7   0.0  90.2  97.4  92.2  80.3  93.5  ...    
1997-03-01  79.2  80.8  73.2  37.0   0.0  90.3  97.5  92.0  80.4  93.2  ...    

            K385  K386   K387  K388  K389  K38A  K38B  K38C  K38D  K38E  
1997-01-01  67.4  79.1  227.0  83.8  82.1  94.0  74.2  88.4  81.1  73.9  
1997-02-01  67.5  79.2  220.9  83.9  82.1  94.2  74.5  88.5  81.1  74.3  
1997-03-01  67.5  79.3  218.9  84.0  82.2  94.3  74.7  88.7  81.1  74.4  

[3 rows x 27 columns]

这是我的第二个数据框的头部，A2：

            K37L  K37M  K37N  K37P  K37Q  K37R  K37S  K37T  K37U  K37V  ...   \
1996-01-01  78.9  79.4  71.7  36.7   0.0  88.7  94.1  90.7  80.2  98.9  ...    
1996-02-01  79.3  81.0  72.7  36.7   0.0  88.7  94.3  90.9  79.8  98.7  ...    
1996-03-01  79.8  80.4  72.7  36.7   0.0  89.0  94.6  91.0  79.6  98.6  ...    

            K385  K386   K387  K388  K389  K38A  K38B  K38C  K38D  K38E  
1996-01-01  70.9  78.7  257.8  83.9  79.7  92.2  73.8  86.4  79.6  74.0  
1996-02-01  70.7  78.7  257.2  83.9  79.8  92.6  73.7  86.6  79.9  73.9  
1996-03-01  70.9  78.7  257.3  83.9  80.1  92.6  73.8  87.2  80.1  74.0  

[3 rows x 27 columns]

我想做的是：A2 /（A1 - 1）* 100

最重要的部分是我想将A1中的所有值除以A2。

我的尝试：

A3 = A2 / (A1-1)*100
print(A3.head(3))

收率：

            K37L  K37M  K37N  K37P  K37Q  K37R  K37S  K37T  K37U  K37V  ...   \
1996-01-01   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN  ...    
1996-02-01   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN  ...    
1996-03-01   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN  ...    

            K385  K386  K387  K388  K389  K38A  K38B  K38C  K38D  K38E  
1996-01-01   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN  
1996-02-01   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN  
1996-03-01   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN   NaN  

[3 rows x 27 columns]

是否可以将整个数据帧（其值）与另一个数据帧分开？或者我将不得不构建某种复杂的循环来实现这一目标？

Answer 1

这是因为pandas将按索引（此处按日期）匹配以应用除法。日期不匹配，因此不会进行任何操作。

你可以试试这个：

A3.index = A1.index  # for instance

然后，您可以重新应用您希望的任何索引：

CREATE OR REPLACE FUNCTION public.get_no_urut_pp (OUT urut1 character varying)
RETURNS character varying AS
$BODY$
BEGIN

    insert into no_urut_pp values (28);
    select max(nomor) into urut1 from no_urut_pp;
END;

$BODY$
LANGUAGE plpgsql VOLATILE
COST 100;

Answer 2

索引不匹配，因此请NaN s

一种可能的解决方案是除以numpy数组，如果两个df具有相同的大小：

A3 = A2 / (A1.values-1)*100
print(A3.head(3))
                  K386        K387        K388       K389       K38A  \
1996-01-01  100.768246  114.070796  101.328502  98.273736  99.139785   
1996-02-01  100.639386  116.962256  101.206273  98.397041  99.356223   
1996-03-01  100.510856  118.081689  101.084337  98.645320  99.249732   

                  K38B       K38C        K38D        K38E  
1996-01-01  100.819672  98.855835   99.375780  101.508916  
1996-02-01  100.272109  98.971429   99.750312  100.818554  
1996-03-01  100.135685  99.429875  100.000000  100.817439

是否可以将一个数据帧与另一个数据帧分开？

2 个答案: