无法使用mplleaflet显示修补程序

Question

我正在尝试在传单地图中显示固定大小的圆圈。

我尝试使用.add_artist()（请参阅here），我现在正尝试使用.add_patch()

import mplleaflet
import matplotlib.pyplot as plt
import matplotlib as mpl

fig, ax = plt.subplots()
x = 2.363561
y = 48.951918
r = 20
circle1 = mpl.patches.Circle((x,y), radius=r)
circle2= plt.Circle((x, y), r, color='r')

#ax.add_patch(circle1)
#ax.add_patch(circle2) 

mplleaflet.show(fig=ax.figure)

您可以尝试取消注释两个注释行中的一行，取消注释哪一行无关紧要，弹出相同的错误。

这是我得到的痕迹：

Traceback (most recent call last):

  File "<ipython-input-81-1fdd7f4a9d12>", line 16, in <module>
    mplleaflet.show(fig = ax.figure)

  File "C:\ProgramData\Anaconda3\lib\site-packages\mplleaflet\_display.py", line 180, in show
    save_html(fig, fileobj=f, **kwargs)

  File "C:\ProgramData\Anaconda3\lib\site-packages\mplleaflet\_display.py", line 131, in save_html
    html = fig_to_html(fig, **kwargs)

  File "C:\ProgramData\Anaconda3\lib\site-packages\mplleaflet\_display.py", line 84, in fig_to_html
    exporter.run(fig)

  File "C:\ProgramData\Anaconda3\lib\site-packages\mplleaflet\mplexporter\exporter.py", line 51, in run
    self.crawl_fig(fig)

  File "C:\ProgramData\Anaconda3\lib\site-packages\mplleaflet\mplexporter\exporter.py", line 118, in crawl_fig
    self.crawl_ax(ax)

  File "C:\ProgramData\Anaconda3\lib\site-packages\mplleaflet\mplexporter\exporter.py", line 138, in crawl_ax
    self.draw_patch(ax, patch)

  File "C:\ProgramData\Anaconda3\lib\site-packages\mplleaflet\mplexporter\exporter.py", line 227, in draw_patch
    mplobj=patch)

  File "C:\ProgramData\Anaconda3\lib\site-packages\mplleaflet\leaflet_renderer.py", line 125, in draw_path
    rings = list(iter_rings(data, pathcodes))

  File "C:\ProgramData\Anaconda3\lib\site-packages\mplleaflet\utils.py", line 14, in iter_rings
    raise ValueError('Unrecognized code: {}'.format(code))

ValueError: Unrecognized code: C

关于如何解决这个问题的任何想法？

===========================

编辑：

为了看看会发生什么，我尝试做的事情与this相同，后者正在改变

elif code == 'L': ring.append(point)

到

elif code == 'L' or code == 'Z' or code == 'S' or code == 'C': ring.append(point)

在mplleaflet\utils.py第11和12行。这是我得到的：

===========================

编辑2回答评论

mpl.patches.Rectangle和plt.Rectangle显示：

rect1 = mpl.patches.Rectangle((x,y), 1, 1, color = 'r')
rect2 = plt.Rectangle((x, y), 1, 1, fc='r')

这似乎适合纬度为1度，经度为1度的矩形（见here）（也许？看起来有点小）。

关于Polygons，嗯......至少他们出现了，但我猜有一个预测问题：

regpol1 = mpl.patches.RegularPolygon((x,y), 100, radius=r, color = 'r')
cirpol1 = mpl.patches.CirclePolygon((x +50,y), radius=r, color = 'b')