在winform设计器

Question

我创建了一个派生自TableLayoutPanel的控件。当我在WinForms设计器中拖放该控件时，右键单击它会显示TableLayoutPanel的默认上下文菜单。

我需要在设计时禁用此控件的默认上下文菜单。我尝试覆盖ContextMenu和ContextMenuStrip，但它没有帮助。

方法1：覆盖ContextMenu

public class MyControl : TableLayoutPanel
{
    public MyControl()
    {
    }
    public override ContextMenu ContextMenu { get => new ContextMenu();}
    public override ContextMenuStrip ContextMenuStrip { get => new ContextMenuStrip(); }
}

方法2：当用户右键点击MyControl时发送ESC键，这样上下文菜单就不会出现

public class MyDesignerForm
{
     ISelectionService service = (ISelectionService)serviceContainer.GetService(typeof(ISelectionService));
     Application.AddMessageFilter(new MyControl(),service);
}
internal class MyMsgFilter : IMessageFilter
       {
            const int WM_RBUTTONDOWN = 0x0204;
            const int WM_KEYDOWN = 0x100;
            const int WM_KEYUP = 0x101;
            const int VK_ESCAPE = 0x1B;
            Control m_control;
            [DllImport("User32.dll")]
            public static extern bool PostMessage(IntPtr hwnd, int uMsg, int wParam, int lParam);
            ISelectionService service = null;
            public MyMsgFilter(Control control,ISelectionService Service)
            {
                this.m_control = control;
                service = Service;
            }
            private void SendEscape(IntPtr hwnd)
            {
                PostMessage(hwnd, WM_KEYDOWN, VK_ESCAPE, 0);
                PostMessage(hwnd, WM_KEYUP, VK_ESCAPE, 0);
            }

            #region IMessageFilter Members
            public bool PreFilterMessage(ref Message m)
            {
                long wParam, lParam;
                bool result;

                if(m.Msg==WM_RBUTTONDOWN)
                {
                    SendEscape(m_control.Handle);
                    return true;
                }
                return false;
            }
            #endregion
        }