if(counter>=keys.count){
NSLog(@"finished");
[_images removeFromSuperview];
// [_alphabetsShowImageView removeFromSuperview];
[_speakerOrMicImageView removeFromSuperview];
UIImageView *congratzView = [[UIImageView alloc]initWithFrame:self.view.frame];
congratzView.image = [UIImage imageNamed:@"congratulation.png"];
[self.view addSubview:congratzView];
}
else{
arrVal = [dictAlpha objectForKey:keys[i]];
if(j>=arrVal.count)
{
NSLog(@"finished");
[_alphabetsShowImageView removeFromSuperview];
[_speakerOrMicImageView removeFromSuperview];
UIImageView *congratzView = [[UIImageView alloc]initWithFrame:self.view.frame];
congratzView.image = [UIImage imageNamed:@"congratulation.png"];
[self.view addSubview:congratzView];
// [self performSelector:@selector(navNew) withObject:nil afterDelay:3];
}
else
{
[commonFunctionObject textToSpeechAction:arrVal :j :_alphabetsShowImageView :_speakerOrMicImageView :isMicPresent];
[NSTimer scheduledTimerWithTimeInterval:10.0 target:self selector:@selector(ActionToCkeckRecordCompletion) userInfo:nil repeats:YES];
}
}
}
输出我需要 - 计数器&LT = keys.count 然后它必须输入if语句条件, 然后j< = arrval.count 然后输入else条件。或者输入if条件循环。 然后如果计数器> = keys.count 然后它必须输入if语句条件
答案 0 :(得分:0)
您正在使用counter
进行迭代,但是您正在使用不同的变量访问数组元素。
您的错误显然意味着计数器和访问者i
& j
可能或可能不等于反制。
您的代码有资格称为快速遍历。您可能还会考虑这种情况的枚举,这将使您免于维护计数器的痛苦;你也可以避免if-else语句。帮助人们保持代码简单!
for(NSString* key in dictAlpha) {
arrVal= [dictAlpha objectForKey:key];
}