Question

我有3个'cdn'文件。

EG。

http://www.cdn.com/js/script1.js (size: 10KB)
http://www.cdn.com/js/script2.js (size: 2KB)
http://www.cdn.com/js/script3.js (size: 15KB)

我需要下载以上3个文件＆amp; concat到'script.js'。通过运行gulp命令，我创建了'script.js'。但是'script.js'中缺少第一个文件（script1.js）。还有其他两个文件。

我改变了订单即。

download(
        [
            "http://www.cdn.com/js/script2.js",(size: 2KB)
            "http://www.cdn.com/js/script3.js",(size: 15KB)
            "http://www.cdn.com/js/script1.js",(size: 10KB)
        ])

这次缺少script3.js，但是script1.js就在那里。

我的'gulp.js'文件

var gulp = require('gulp');
var del = require('del');
var download = require("gulp-download-stream");
var concat = require('gulp-concat');

var FileSystem = require('fs');
var PackageJSON = JSON.parse(FileSystem.readFileSync('package.json'));
var Destination = "cdn/"+PackageJSON.version;

gulp.task('clean', function() 
{
    return del([Destination]);
});

gulp.task('js', function() 
{
    download(
    [
        "http://www.cdn.com/js/script1.js",
        "http://www.cdn.com/js/script2.js",
        "http://www.cdn.com/js/script3.js",
    ])
    .pipe(gulp.dest("temp/"));
    return gulp.src("temp/*.js")
    .pipe(concat('script.js'))
    .pipe(gulp.dest(Destination+"/"));
});

gulp.task('default', ['clean','js']);

'的package.json'

{
    "name": "",
    "version": "4.0.0",
    "description": "",
    "main": "",
    "dependencies":
    {
        "gulp": "^3.9.1"
    },
    "devDependencies":
    {
        "del": "^3.0.0",
        "gulp": "^3.9.1",
        "gulp-concat": "^2.6.1",
        "gulp-download-stream":"^0.0.1"
    },
    "scripts":
    {
        "test": "echo \"Error: no test specified\" && exit 1"
    },
    "author": "",
    "license": "ISC"
}

提前致谢

Answer 1

您最初可能已经拥有此功能，但请在数组中查看尾随逗号：

 download(
[
    "http://www.cdn.com/js/script1.js",
    "http://www.cdn.com/js/script2.js",
    "http://www.cdn.com/js/script3.js"
])

我删除了最后一个逗号。也许这会破坏你的下载电话。

下载＆amp;使用gulp的concat js文件

1 个答案: