Question

是python的新手我在这附近有一个嵌套列表，

[['Elevation 3,000 feet'], [' Ground Snow Load is0 '], ['Elevation > 3,000 and 4,500 feet'], [' Ground Snow Load is5 '], ['Elevation > 4,500 and 5,400 feet'], [' Ground Snow Load is10 ']]

从上面的嵌套列表中我想从列表中得到基本数字。

我的最终列表应该是，

[['3000'], ['0'], ['3000','4500'], ['5'], ['4500' , '5400'], ['10']]

提前谢谢你们。

Answer 1

你没有写任何代码，所以我不会给你一个完整的解决方案。

>>> data = [['Elevation 3,000 feet'], [' Ground Snow Load is0 '], ['Elevation > 3,000 and 4,500 feet'], [' Ground Snow Load is5 '], ['Elevation > 4,500 and 5,400 feet'], [' Ground Snow Load is10 ']]
>>> import re
>>> [re.findall('\d+',l[0]) for l in data]
[['3', '000'], ['0'], ['3', '000', '4', '500'], ['5'], ['4', '500', '5', '400'], ['10']]

现在您只需首先删除,，或在正则表达式中接受混合数字和,。

Answer 2

包含太多，但有效。（假设＆＃34;列表＆＃34;中的每个列表中只有一个项目。它可以修复。）

lists = [['Elevation 3,000 feet'], [' Ground Snow Load is0 '], ['Elevation > 3,000 and 4,500 feet'], [' Ground Snow Load is5 '], ['Elevation > 4,500 and 5,400 feet'], [' Ground Snow Load is10 ']]
result = []
for list in lists:
    numbers = []
    str = list[0].replace(",", "").replace(".", "")
    for word in str.split():    #separate from space
        number = ""
        for char in word:
            if char.isdigit():
                number += char 
        if number:      
            numbers.append(number)  
    result.append(numbers)

print (result)

输出：

[['3000'], ['0'], ['3000', '4500'], ['5'], ['4500', '5400'], ['10']]

从嵌套列表中提取数字

2 个答案: