这是我父组件的html模板。 自定义标记用于包含我的子组件以显示帖子对象 我已连接快速服务器,所有查询都是通过HTTP与服务完成的。 每次添加新的帖子对象时,UI都不会更新。
我知道我需要将事件传递给子组件,但到目前为止我还没有成功。
/ * app.component.html * / 在这个模板中我试图用(onAdded)=“onAdded($ event)”
绑定方法
<div class="collapse navbar-collapse" id="navbarSupportedContent">
<ul class="navbar-nav mr-auto links">
<li class="nav-item">
<a class="btn btn-secondary" routerLink="/posts" href="javascript:void(0);" (click)="addToBoard()"> <i class="fa fa-plus-square fa-3x" aria-hidden="true"></i></a>
</li>
</ul>
</div>
</div>
的
/ * app.component.ts(PARENT)* /
import { Component, OnInit, **EventEmitter, Output**} from '@angular/core';
import { Post } from './shared/post';
import { PostService } from './services/post.service';
@Component({
selector: 'app-root',
templateUrl: './app.component.html',
styleUrls: ['./app.component.css'],
providers: [PostService]
})
export class AppComponent implements OnInit {
@Output() onAdded = new EventEmitter<Post>();
title = 'Post it Board';
posts: Post[];
private newPost :Post;
constructor(private postService: PostService) { }
ngOnInit(): void {
this.getPosts()
this.newPost = {
text: 'some text',
_id: ''
}
}
addToBoard(): void {
this.postService.addPost(this.newPost).subscribe(
response=> {
if(response.success== true)
//If success, update the view-list component
console.log('success')
**this.onAdded.emit(this.newPost);**
},
);
}
getPosts() {
this.postService.getAllPosts().subscribe(
response => this.posts = response,)
}
}
/ view-board.component.ts(CHILD) /
import { Component, OnInit} from '@angular/core';
import { Post } from '../shared/post';
import { POSTS } from '../shared/mock-posts';
import { PostService } from '../services/post.service';
@Component({
selector: 'view-board',
templateUrl: './view-board.component.html',
styleUrls: ['../css/style.css'],
providers: [PostService]
})
export class ViewBoardComponent implements OnInit {
title = "Post it"
posts: Post[];
constructor(private postService: PostService) { }
ngOnInit() {
this.getPosts()
}
getPosts() {
this.postService.getAllPosts().subscribe(
response => this.posts = response,)
}
**onAdded(post: Post) {
console.log('new post added ' + post.text)
this.posts = this.posts.concat(post);
}**
}
感谢您的帮助!
答案 0 :(得分:1)
不,如果你想从Child传递给Parent,你必须做事件发送,在这种情况下,你可以作为输入传递给子元素。
内部父组件。
<view-board [success]="success">
并在您的子组件中
@Input() success: string;