Question

有人可以帮助我解决我的问题，我有2个表

查询表一：

  SELECT (REPLACE(A .coano, '0', '')) coano_for_like FROM glfcoa_dump A WHERE posum = 'K' ORDER BY A .coano ASC;

表一的结果：

coano_for_like 
----------------
1
11
12
13
131
132
2
21
211
212
22
221
2211
292
2921
2922
2923
2924
293

查询表二：

SELECT
    coano,
    SUM (CAST(endbal AS NUMERIC)) endbal
FROM
    vw_fx_glfmas
WHERE
    OFCID = '450'
AND TGL = '2017-08-11' and coano like '11%'
GROUP BY 
    coano
ORDER BY
    SUBSTRING (coano ,- 2, 7) ASC

结果对于表二：

coano   endbal
--------------
111000  0
112000  234342846
114000  0

表2中的

coano like '11%' 11是表一的结果

我的问题，如何从结果表一中按表2中的所有coano分组？

我想要这样的结果：

coano_for_like  coano   endbal
----------------------------------
1               111000  0
                112000  234342846
                114000  0
                152101  813307251
                152102  49259791
                162110  -3456957
                163010  0
                169100  -36826000
                169200  -32649000
11              111000  0
                112000  234342846
                114000  0
12              ...     ...

Answer 1

我认为您需要在第二个查询中更改GROUP BY和SELECT，以便通过您在查询1中使用的REPLACE函数进行分组：

SELECT
a.coano_for_like,
b.coano,
SUM (CAST(b.endbal AS NUMERIC)) AS endbal
FROM 
  (SELECT REPLACE(coano, '0', '') AS coano_for_like
  FROM  glfcoa_dump) AS a
INNER JOIN vw_fx_glfmas b ON a.coano_for_like = b.coano
WHERE b.ofcid = '450'
AND b.tgl = '2017-08-11'
AND b.posum = 'K'
GROUP BY a.coano_for_like,
b.coano
ORDER BY A.coano ASC;

这能为您提供所需的结果吗？

Answer 2

您可以在联接中使用like。

SELECT coano_for_like, coano, SUM (CAST(endbal AS NUMERIC)) endbal
  FROM vw_fx_glfmas 
  JOIN (SELECT (REPLACE(A .coano, '0', '')) coano_for_like FROM glfcoa_dump A WHERE posum = 'K') r
 WHERE OFCID = '450' AND TGL = '2017-08-11' and coano like coano_for_like || '%'
 GROUP BY coano
 ORDER BY coano ASC

略微纠正

SELECT
    r.coano_for_like,
    coano,
    SUM (CAST(endbal AS NUMERIC)) endbal
FROM
    vw_fx_glfmas a,
    (
        SELECT
            (REPLACE(A .coano, '0', '')) coano_for_like
        FROM
            glfcoa_dump A
        WHERE
            posum = 'K'
    ) r
WHERE
    ofcid = '450'
AND TGL = '2017-08-11'
AND coano LIKE coano_for_like || '%'
GROUP BY
    coano_for_like,
    a.coano
ORDER BY
    coano_for_like ASC

每个id都像postgres一样

2 个答案: