The DEMO

Question

现在我有一个控制器并设置一些如下的功能。我想在回调函数中获取变量data2。但现在它还没有定义。

＆＃13;

var searchApp = angular.module('reveal.searchUI');

searchApp.controller('SearchController', ['$rootScope','$scope','$q','$http','$timeout','$window',
    '$i18next', '$filter','$sanitize', '$cookies',
    'emcui.EventBus','RemoteUrl',"Reveal","Cache","AUTH_EVENTS",
    function($rootScope, $scope, $q, $http, $timeout, $window, $i18next,
             $filter, $sanitize,$cookies, eventBus,remoteUrlProvider, reveal,
             cache, AUTH_EVENTS){
        var self = this;
        var data1 = "data1";
        this.testing = function(){
          var data2 = "data2";
          setTimeout(function(){
            //need to get the variable data2
            },1000);
        };
    }]);

＆＃13;

Answer 1

代码能够在回调中访问data2。

确保该示例实际上重现了该问题！如果您在编写示例时无意中修复了问题但又没有再次测试，那么在询问之前您还是想知道这个问题别人帮忙。

The DEMO

＆＃13;

angular.module("app",[])
.controller('SearchController', [
    function(){
        var self = this;
        var data1 = "data1";
        this.testing = function(){
          var data2 = "data2";
          setTimeout(function(){
            //need to get the variable data2
            console.log(data2);
            },1000);
        };
}]);

＆＃13;

<script src="//unpkg.com/angular/angular.js"></script>
  <body ng-app="app" ng-controller="SearchController as vm">
    <button ng-click="vm.testing()">Click me</button>
  </body>

＆＃13;

在回调函数中无法获取外部变量值

1 个答案:

The DEMO