Question

我有一个包含公司对象的列表列表：

companies_list = [companies1, companies2]

我有以下功能：

def get_fund_amount_by_year(companies_list):
    companies_length = len(companies_list)
    for idx, companies in enumerate(companies_list):
        companies1 = companies.values_list('id', flat=True)
        funding_rounds = FundingRound.objects.filter(company_id__in=companies1).order_by('announced_on')

        amount_per_year_list = []
        for fr in funding_rounds:
            fr_year = fr.announced_on.year
            fr_amount = fr.raised_amount_usd
            if not any(d['year'] == fr_year for d in amount_per_year_list):
                year_amount = {}
                year_amount['year'] = fr_year
                for companies_idx in range(companies_length):
                    year_amount['amount'+str(companies_idx)] = 0
                    if  companies_idx == idx:
                        year_amount['amount'+str(companies_idx)] = fr_amount
                amount_per_year_list.append(year_amount)
            else:
                for year_amount in amount_per_year_list:
                    if year_amount['year'] == fr_year:
                        year_amount['amount'+str(idx)] += fr_amount

    return amount_per_year_list

问题是生成的词典列表只更新了一个数量属性。

如您所见，“amount0”包含所有“0”金额：

[{'amount1'：12100000L，'amount0'：0，'year'：1999}，{'amount1'： 8900000L，'amount0'：0，'年'：2000}]

我做错了什么？

Answer 1

我把循环中构建的字典列表放在循环中，所以当迭代它覆盖最后一个输入时。我改变它看起来像：

def get_fund_amount_by_year(companies_list):
    companies_length = len(companies_list)
    **amount_per_year_list = []**
    for idx, companies in enumerate(companies_list):
        companies1 = companies.values_list('id', flat=True)
        funding_rounds = FundingRound.objects.filter(company_id__in=companies1).order_by('announced_on')

python词典列表只更新1个属性并跳过其他属性

1 个答案: