Question

我正在使用MS SQL Server 2014和Coldfusion 10，并且正在我的桌面上发布问题。创建pdf时，我的桌面上某些用户的My Associate Total会被跳过。有没有人知道我做错了什么会让一些用户跳过Associate Total字段？

<cfset date1 = CREATEODBCDATETIME(form.StartDate & '00:00:00')>
<cfset date2 = CREATEODBCDATETIME(form.EndDate & '23:59:59')>

<!--- WHITELIST OF VALID LOCATIONS --->
    <cfset validLocs = "OPERATIONS, CCC, QA, DS, PS, LWR, NR, SDL, FSC">
    <cfset locList = "">
    <cfif structKeyExists(FORM,"location") AND len(FORM.location) GT 0>
        <cfloop list="#FORM.location#" index="vLoc"> 
            <cfif listContainsNoCase(validLocs, vLoc) GT 0> 
            <cfset locList = listAppend(locList,vloc)>
            </cfif> 
        </cfloop> 
    <cfelse>
    </cfif>


<cfquery datasource="#application.dsn#" name="GetEmployeeInfo">
    SELECT * 
      FROM ( 
        SELECT t1.associate 
        , a.assoc_name 
        , t1.trans_location 
        , t1.checklistsByAssocLoc 
        , t1.totalChecklistsByAssoc 
        , CASE WHEN ( coalesce(t1.totalChecklistsByAssoc,0) > 0 ) THEN (CAST(t1.checklistsByAssocLoc AS decimal(8,2))/t1.totalChecklistsByAssoc) * 100 ELSE 0 END AS totalChecklistsByAssocLocPct /* This gives you a percent of associate location checklists over count of checklists by Associate */ , t1.totalChecklistsByLoc 
        , CASE WHEN ( coalesce(t1.totalChecklistsByLoc,0) > 0 ) THEN (CAST(t1.checklistsByAssocLoc AS decimal(8,2))/t1.totalChecklistsByLoc) * 100 ELSE 0 END AS totalChecklistsByLocPct /* This gives you a percent of associate location checklists over count of checklists by Location */ 
        , ROW_NUMBER() OVER (PARTITION BY associate ORDER BY associate, trans_location) AS rnA 
        , ROW_NUMBER() OVER (PARTITION BY associate, trans_location ORDER BY trans_location) AS rnL 
        , t1.rnTotAssoc 
      FROM ( 
        SELECT c.associate 
        , c.trans_location 
        , COUNT(*) OVER (PARTITION BY c.associate, c.trans_location) AS checklistsByAssocLoc /* Gives you a count of checklists by Associate and Location >> I think this is 1.1 locCntr */ 
        , COUNT(*) OVER (PARTITION BY c.associate) AS totalChecklistsByAssoc /* Gives you a count of checklists by Associate */ 
        , COUNT(*) OVER (PARTITION BY c.trans_location) AS totalChecklistsByLoc /* Gives you a count of checklists by Location */ 
        , ROW_NUMBER() OVER (PARTITION BY c.associate ORDER BY c.trans_location DESC) AS rnTotAssoc 
      FROM cl_checklists c 
      WHERE c.[DATE] >= <cfqueryparam value="#date1#" cfsqltype="cf_sql_timestamp" /> 
        AND c.[DATE] <= <cfqueryparam value="#date2#" cfsqltype="cf_sql_timestamp" /> 
        AND c.trans_location IN ( <cfqueryparam value="#locList#" cfsqltype="cf_sql_varchar" list="true" />  )
      ) t1 
        INNER JOIN tco_associates a ON t1.associate = a.assoc_id 
      ) s2 
      WHERE s2.rnA = 1 OR s2.rnL = 1 
      ORDER BY s2.assoc_name, s2.trans_location 
</cfquery>  

<cfif GetEmployeeInfo.recordcount is 0>

<td width="85%" valign="top" class="mainmodule"><p class="pageheader">CHECKLIST STATS REPORT</p><br />
    No matching records found
</td>
</tr>
</table>

</body>
</html>

<cfelse>

<cfif FORM.Format IS "print">

<cfdocument format="pdf" scale="75" backgroundvisible="yes" overwrite="no" fontembed="yes">

<td width="85%" valign="top" class="mainmodule"><p class="pageheader">CHECKLIST STATS REPORT</p><br />

<style type="text/css">
    table{
      text-align:center;
    }
</style>

<table>
    <thead>
        <th><strong>Associate Name</strong></th>
        <th><strong>Location</strong></th>
        <th><strong>Checklists Generated by Associate</strong></th>
        <th><strong>Checklists Generated by Selected Location(s)</strong></th>
        <th><strong>Associate Percentage of Location Total</strong></th>   
    </thead>
    <tbody>
        <cfoutput query="GetEmployeeInfo">
      <tr>
          <td><cfif rnA EQ 1><strong>#assoc_name#</strong></cfif></td>
          <td><cfif rnL EQ 1>#trans_location#</cfif></td>
          <td>#checklistsByAssocLoc#</td>
          <td>#totalChecklistsByLoc#</td>
          <td>#DecimalFormat(totalChecklistsByLocPct)# %</td>
      </tr>
      <cfif rnTotAssoc EQ 1> 
      <tr> 
          <td>Associate Total</td> 
          <td></td> 
          <td>#totalChecklistsByAssoc#</td> 
          <td>#totalChecklistsByLoc#</td> 
          <td>#DecimalFormat(totalChecklistsByLocPct)# %</td> 
      </tr>
      </cfif>
    </cfoutput>
    </tbody>
</table>

</cfdocument>

</cfif>

</cfif>

结果应该如下：

Brierton, David SDL 1 32195 0.00 % 
Associate Total     1 32195 0.00 %

有些显示为：

Brierton, David SDL 1 32195 0.00 %

Answer 1

该查询看起来正确。

rnA = 1将给出包含关联名称的第一个实例的行。

rnL = 1将为该位置的第一个实例提供行。

rnTotAssoc = 1将给出一个关联的最后一行，包括他们的位置。下一行应显示关联记录的总数。每位员工应至少拥有1条rnTotAssoc = 1的记录。

http://sqlfiddle.com/#!6/56892/10

你有糟糕的数据会弄乱结果吗？尝试挑出一两个人，并提出他们应该正确的计数。您可以从查询中删除WHERE s2.rnA = 1 OR s2.rnL = 1以查看进入这些计数的所有行。

CF表在创建表时跳过行

1 个答案: