Question

就我而言，我正在根据学院名称，地点和课程开设搜索培训机构

我有3张桌子

 public function locations()
 {
     return $this->hasMany(Location::class);
 }
  public function courses()
 {
     return $this->hasMany(Course::class);
 }

我创建了3个表格之间的关系

学院模型：

 public function institute()
 {
     return $this->belongsTo(Institute::class);
 }

课程模型：

  public function institute()
  {
     return $this->belongsTo(Institute::class);
  }

位置模型：

  public function filter(Request $request)
  {
       $institute = (new Institute)->newQuery();

       // Search for a user based on their institute.

       if ($request->has('institute_name')) {
       $institute->where('institute_name', $request->input('institute_name'));
       }

      // Search for a user based on their course_name.

      if ($request->has('course_name')) {
      $institute->whereHas('courses', function ($query) use ($request) {
      $query->where('courses.course_name', $request->input('course_name'));
      });
      }

      // Search for a user based on their course_name.           

      if ($request->has('location_name')) {
      $institute->whereHas('locations', function ($query) use ($request) {
      $query->where('locations.location_name', $request->input('location_name'));
      });
      }
      return response()->json($institute->get());
  }

所以我试过下面的代码

  [
      {
          "id": 2,
          "institute_name": "qspider",
          "institute_contact_number": "9903456789",
          "institute_email": "qspider@gmail.com",
          "status": "1",
      }
  ]

从上面的代码我可以过滤数据，但它只显示机构表数据，如下所示。

SELECT Subject.ID, Subject.Description, Max(DataSets.ID) AS ID_DataSets
FROM Subject 
INNER JOIN DataSets ON Subject.Description = DataSets.Subject.Value
GROUP BY Subject.ID, Subject.Description;

但我需要的是当我使用course_name或instute_name进行搜索时，我需要从institues表，课程和位置表中获取数据。有人可以帮忙吗？

Answer 1

急切加载if语句中的关系。

  // Search for a user based on their course_name.
  if ($request->has('course_name')) {
      $institute->whereHas('courses', function ($query) use ($request) {
          $query->where('courses.course_name', $request->input('course_name'));
      })
      ->with('courses); // <<<<<< add this line
  }

  // Search for a user based on their course_name.           
  if ($request->has('location_name')) {
      $institute->whereHas('locations', function ($query) use ($request) {
          $query->where('locations.location_name', $request->input('location_name'));
      })
      ->with('locations'); // <<<<<<< add this line
  }

这也将获取相关的课程和位置。

laravel中的高级过滤器

1 个答案: