Question

尝试重复嵌套for循环中的数组：

#!/bin/bash

aaa=("nine" "ten" "eleven" "twelve")
bbb=("one" "two" "three" "four" "five" "six" "seven" "eight")
ccc=("thirteen" "fourteen")


for b in "${bbb[@]}" ; do
    for i in "${!aaa[@]}" ; do
        echo "$b" "${aaa[i]}" "${ccc[i]}"
    done
done

我明白这一点，11行和12行不会收到ccc元素：

one nine thirteen
one ten fourteen
one eleven 
one twelve 
two nine thirteen
two ten fourteen
two eleven 
two twelve 
three nine thirteen
three ten fourteen
three eleven 
three twelve 
four nine thirteen
four ten fourteen
four eleven 
four twelve 
five nine thirteen
five ten fourteen
five eleven 
five twelve 
six nine thirteen
six ten fourteen
six eleven 
six twelve 
seven nine thirteen
seven ten fourteen
seven eleven 
seven twelve 
eight nine thirteen
eight ten fourteen
eight eleven 
eight twelve

期望的输出：

one nine thirteen
one ten fourteen
one eleven thirteen
one twelve fourteen
two nine thirteen
two ten fourteen
two eleven thirteen
two twelve fourteen
three nine thirteen
three ten fourteen
three eleven thirteen
three twelve fourteen
four nine thirteen
four ten fourteen
four eleven thirteen
four twelve fourteen
five nine thirteen
five ten fourteen
five eleven thirteen
five twelve fourteen
six nine thirteen
six ten fourteen
six eleven thirteen
six twelve fourteen
seven nine thirteen
seven ten fourteen
seven eleven thirteen
seven twelve fourteen
eight nine thirteen
eight ten fourteen
eight eleven thirteen
eight twelve fourteen

Answer 1

从预期输出中，您需要一个模"${ccc[i%${#ccc[@]}]}"而不是"${ccc[i]}"

Answer 2

试试这个

aaa=("nine" "ten" "eleven" "twelve")
bbb=("one" "two" "three" "four" "five" "six" "seven" "eight")
ccc=("thirteen" "fourteen")
echo ${!aaa[@]}
count=0;
for b in "${bbb[@]}" ; do
    for i in "${!aaa[@]}" ; do
        (( count = count==1 ? 0 : 1 ))
        echo "$b" "${aaa[i]}" "${ccc[count]}"
    done
done

Bash：在for循环中重复数组

2 个答案: