Question

我在解决这部分问题时遇到了问题。即使看起来很容易我花了几天时间调试它。所以，我有一个包含6个选项的菜单。例如：

购买针好晚上！
购买quaffles
做服务套件
显示价目表
查看
（我不确定是否需要将其写为if else语句）必要时再次执行循环。

一开始我尝试使用switch语句，但我无法使用一个案例中的值并在另一个案例中使用它。所以我试着写这个，但问题是，一旦我选择选项1，它将只显示选项1，无论我输入的是什么数字。

answermenuoption = inScan.nextInt();

while (answermenuoption != menustop) ;
{

    if (answermenuoption == 1) {
        prompt = "Please enter another item from the menu above: ";
        if (answermenuoption == 1) {

            System.out.println("How many pins do you want to buy?");

            pins = inScan.nextInt();

            if (pins > 10) {
                pricepins = pins * 18;
                System.out.println("Thank you.Your order received");

                System.out.println(menu);
            } else {
                pricepins = pins * 20;
                System.out.println("Thank you.Your order received");
                System.out.println(menu);
            }

        } else if (answermenuoption == 2) {
            System.out.println("How many quaffles do you want to buy?");
            quaffles = inScan.nextInt();

            if (quaffles > 5) {
                quafflesbox = quaffles / 5;
                quafflesindividual = quaffles % 5;
                pricequafflesbox = 580 * quafflesbox;
                pricequafflesindividual = quafflesindividual * 145;
                pricequaffles = quafflesbox * 580 + quafflesindividual * 145;

                System.out.println("Thank you.Your order received");
                System.out.println(menu);
            } else {
                pricequaffles = quafflesindividual * 145;
                System.out.println("Thank you.Your order received");
                System.out.println(menu);
            }

        } else if (answermenuoption == 3) {
            System.out.println("How many broomstick service kit do you want to buy?");
            broomsticks = inScan.nextInt();
            pricebroomsticks = broomsticks * 899;

            System.out.println("Thank you.Your order received");
            System.out.println(menu);
        } else if (answermenuoption == 4) {
            System.out.println(pricemenudiscount);
            System.out.println(menu);

        } else if (answermenuoption == 5) pricetotal = pricequaffles + pricebroomsticks + pricepins;

        if (pricetotal > 1493) {

            discountapplied = pricetotal * 0.1;
            pricetotal = pricetotal - discountapplied;

            System.out.println("The total price is:" + pricetotal);
            System.out.println("Price of pins:" + pricepins);
            System.out.println("Price of quaffles" + pricequaffles);
            System.out.println("Price for quaffles in the box of 5 = " + pricequafflesbox);
            System.out.println("Price for single quaffles = " + pricequafflesindividual);
            System.out.println("Price for broomstick service kits = " + pricebroomsticks);
            System.out.println("Discount applied: = " + discountapplied);

            System.out.println("Please input the money amount: ");
            moneyinput = inScan.nextInt();

            changetocustomer = moneyinput - pricetotal;
            System.out.println("Your change is:" + changetocustomer);
        } else {
            System.out.println("The total price is:" + pricetotal);
            System.out.println("Price of pins:" + pricepins);
        }
    }
}

Answer 1

您只能在循环开始时阅读answermenuoption。

试试这个：

int answermenuoption = inScan.nextInt();
        do
        {
            if(answermenuoption == 1)
            {
             //insert code
            }
            if(answermenuoption==2)
            {
            //insert code
            }

            //....

        }while((answermenuoption=inScan.nextInt())!=menustop);

另请注意，此操作将始终至少运行一次。如果您希望它能够退出第一个值，只需在第一个if语句

之前添加以下代码

if(answermenuoption == menustop)
    break;

带循环的菜单选项

1 个答案: