Question

然后我想单独选择团队：西汉姆联队奥兰多海盗队凯泽酋长埃弗顿... 我决定使用split将它们添加到Array上，这样我就可以使用它们的索引号来选择它们。我得到了第一支球队和最后一支球队，但是我之间的球队得到了类似的结果：的println（choose_team [3]）; 曼联阿森纳，但我个人想要他们。请看代码！任何解决方案？

字符串答案=＆＃34;＆＃34 ;;

//以下字符串游戏是我要提取和存储的团队示例。

    String games = "West Ham United - Orlando Pirates Kaizer Chiefs - Everton  Liverpool - Manchester United Arsenal - Real Madrid";

    // below I want to split and store as an array

    String[] numbers = games.split("-");  

    System.out.println("splited String variable after loop:");

    for(String ans : numbers){ 

    System.out.println(ans); 

        answer += ans + "-"; } 

        answer = answer.substring(0,answer.length()-1); 

    String[] choose_team = answer.split("-");


      System.out.println("the - sign is re-instated:" + "\n" + answer);

    //  I want to get the teams individually and a print statement is just showing what I want but I'm going to use the teams somewhere else in a code.

      System.out.println("splited string with index 4: " + "\n" + choose_team[0]);

   System.out.println("splited string with index 0: " + "\n" + choose_team[4]);

    System.out.println("splited string with index 1: " + "\n" + choose_team[1]);

    System.out.println("splited string with index 2: " + "\n" + choose_team[2]);

Answer 1

如果我理解你的问题，我认为这可以提供帮助

 final String games = "Team Alfa - Team Bravo Team Charlie - Team Delta Team Echo - Team Foxtrot Team Golf - Team Hotel";
    final String[] numbers = games.split("(?=Team)");
    final List teams = new ArrayList<String>();
    System.out.println("splited String variable after loop:");

    for (String ans : numbers) {
        ans = ans.replaceAll("[-+^]*", "");
        System.out.println(ans);
        teams.add(ans);
    }
    for (int i = 0; i < teams.size(); i++) {
        System.out.println("Team No. " + i + " " + teams.get(i));
    }

我从数据库循环团队并得到结果（示例）是：阿尔法团队 - Team Bravo Team Charlie - Team Delta

1 个答案: