将地图数组json转换为csv

时间:2017-09-20 09:40:19

标签: python json csv

大家好,我对python很新,所以请耐心等待。 我有一个这种格式的示例json文件。

[{
"5":"5",
"0":"0",
"1":"1"},{
"14":"14",
"11":"11",
"15":"15"},{
"25":"25",
"23":"23",
"22":"22"}]

我想以特定的方式将json文件转换为csv。 1映射中的所有值,即json中的{}都应该转换为csv文件(比如FILE_A.csv)。

对于上面的例子,

FILE_A.csv,

DAILY,COUNT
5,5
0,0
1,1

FILE_B.csv,

WEEKLY,COUNT
14,14
11,11
15,15

FILE_C.csv,

MONTHLY,COUNT
25,25
23,23
22,22

json中只有3张地图。

有人能建议将json中的3个地图转换为上述结构的3个不同csv文件的最佳方法吗?

提前致谢。

3 个答案:

答案 0 :(得分:0)

您可以使用包含所需数据的简单循环,如下所示:

jsondata = [{
"5":"5",
"0":"0",
"1":"1"},{
"14":"14",
"11":"11",
"15":"15"},{
"25":"25",
"23":"23",
"22":"22"}]

for name, timelapse, data in zip(("A", "B", "C"), 
                                 ("DAILY", "WEEKLY","MONTHLY",), 
                                 jsondata): #get data together
    with open("path/to/your/FILE_{}".format(name), "w") as f:
        f.write("{}, COUNT\n".format(timelapse)) # write header
        f.write("\n".join(",".join((k,v)) for k,v in data.items())) #write data separated by ','

这里有live example

另请查看csv模块

答案 1 :(得分:0)

data_list = [{
"5":"5",
"0":"0",
"1":"1"},{
"14":"14",
"11":"11",
"15":"15"},{
"25":"25",
"23":"23",
"22":"22"}]

temp_dct = { "DAILY": data_list[0], "WEEKLY": data_list[1], "MONTHLY": data_list[2]}
file_name_ord = 65
for k in ["DAILY", "WEEKLY", "MONTHLY"]:
    v = temp_dct[k]
    file_name = "FILE_"+str(chr(file_name_ord))+".csv"
    file_name_ord+=1
    data = k + ","+ "COUNT\n" 
    for inner_k, inner_v in v.items():
        data += inner_k + ","+inner_v+"\n"

    with open(file_name, "w") as f:
        f.write(data)

也尝试这个。希望你能得到答案。

答案 2 :(得分:0)

直接解决方案:

import json, csv    

with open('FILE_A.csv', 'w', newline='') as fa, open('FILE_B.csv', 'w', newline='') as fb, \
     open('FILE_C.csv', 'w', newline='') as fc:

    a_writer, b_writer, c_writer = csv.writer(fa), csv.writer(fb), csv.writer(fc)
    da, db, dc = json.load(open('your.json'))

    a_writer.writerow(('DAILY','COUNT'))
    a_writer.writerows(da.items())

    b_writer.writerow(('WEEKLY','COUNT'))
    b_writer.writerows(db.items())

    c_writer.writerow(('MONTHLY','COUNT'))
    c_writer.writerows(dc.items())