Question

重写问题，因为命名捕获组不是主要问题。

/([a-zA-Z ]*)([0-9]*)/g

代码现在正常工作，但var m = /([a-zA-Z ]*)([0-9]*)/g.exec('Ashok : 9830011245')只给了我Ashok作为结果。

m[0]: "Ashok"
m[1]: "Ashok"
m[2]: ""

示例字符串我需要处理它：

var strings = [
"Ashok : 9812340245",
"Amit Singh :\nChakmir 9013123427\n\nHitendra Singh:\n\nM. : 9612348943",
"ANIL  AGARWAL :  \n09331234728\n09812340442\nMAYANK AGARWAL : \n09123416042",
"JAGDISH SINGH :      098123452187 \n09830111234",
"MD QYAMUDDIN : 09433186333,\n09477215123\nMD TAJUDDIN : \n09831429111\nGYASUDDIN ANSARI :\n08961383686 \nMD BABUDDIN : \n09433336456 \n09903568555\nJAWE",
"Viay Singh : 9330938789,\nBijay Singh : 9330938222",
"Nilu :          09830161000,\n09331863222,\n09830071333,\nSantosh Upadhayay :       09831379555,\n09331727858,\n09830593322"
];

请指导。

Answer 1

您似乎可以使用

提取所需的所有子字符串

/^([^:0-9\n]+)\s*(?::\s*)?([0-9]*)/gm

请参阅regex demo。

<强>详情

^ - 行的开头（因为m启用了多行模式）
([^:0-9\n]+) - 除:以外的1个或多个字符，数字和换行符
\s* - 一个或多个空格
(?::\s*)? - :和0+空格的可选序列
([0-9]*) - 零个或多个数字。

JS演示：

var strings = [
"Ashok : 9812340245",
"Amit Singh :\nChakmir 9013123427\n\nHitendra Singh:\n\nM. : 9612348943",
"ANIL  AGARWAL :  \n09331234728\n09812340442\nMAYANK AGARWAL : \n09123416042",
"JAGDISH SINGH :      098123452187 \n09830111234",
"MD QYAMUDDIN : 09433186333,\n09477215123\nMD TAJUDDIN : \n09831429111\nGYASUDDIN ANSARI :\n08961383686 \nMD BABUDDIN : \n09433336456 \n09903568555\nJAWE",
"Viay Singh : 9330938789,\nBijay Singh : 9330938222",
"Nilu :          09830161000,\n09331863222,\n09830071333,\nSantosh Upadhayay :       09831379555,\n09331727858,\n09830593322"
];

var regex = /^([^:0-9\n]+)\s*(?::\s*)?([0-9]*)/gm;
for (var s of strings) {
  console.log("Looking in: ", s, "\n--------------------------");
	console.log(s.match(regex));
}
// To output groups:
console.log("====Outputting groups====");
for (var s of strings) {
	while(m=regex.exec(s))
    console.log(m[1].trim(), ";", m[2]);
}

Javascript Regex无效组

1 个答案: