Question

我刚开始学习C＃而且遇到了问题。

namespace ConsoleApp3
{
    class Program
    {
        static void Main(string[] args)
        {
            Console.WriteLine("This is a text adventure! <press space to continue>");
            Console.ReadKey();
            do
            {
                Console.WriteLine("A monster aproaches what do you do? <Attack,Flee>");
                string a = Console.ReadLine();
            } while(a != "Attack" && a != "Flee"); 

        }
    }
}

任何帮助都会有用。

Answer 1

我认为您应该将a声明为do块之外的字符串变量，如下所示：

string a = "";

do
{
    Console.WriteLine("A monster aproaches what do you do? <Attack,Flee>");
    a = Console.ReadLine();
} while (a != "Attack" && a != "Flee");

while倾向于Main方法范围，因此a必须存在Main才能在do块内分配。

Answer 2

希望错误是＆＃39; a＆＃39;变量，修复就在这里......

＆＃39;一个＆＃39;变量必须在循环之前声明，你可以为＆＃39; a＆＃39;分配值。在循环内部进行迭代

    class Program
    {
     static void Main(string[] args)
     {
      Console.WriteLine("This is a text adventure! <press space to continue>");
      string a ;
      do
       {
       Console.WriteLine("A monster aproaches what do you do? <Attack,Flee>");
       a = Console.ReadLine();
     } while(a != "Attack" && a != "Flee"); 

    }
    }

Answer 3

范围，如果a只到结束括号。在外面宣布它而不是使用它。

 string a = "";
        Console.WriteLine("This is a text adventure! <press space to continue>");
        Console.ReadKey();
        do
        {
            Console.WriteLine("A monster aproaches what do you do? <Attack,Flee>");
            a = Console.ReadLine();
        } while (a != "Attack" && a != "Flee");

Answer 4

你只需要做这个字符串a =“”;在使用readline设置字符串之前，您可以像尝试一样使用它。祝好运！：）

当前上下文中不存在名称“..”

4 个答案: