Question

我有一个应用程序，我已经实现了谷歌+登录。我检查了所有的代码，并在dubugging后发现它总是在onConnectionFailed（ConnectionResult结果）中抛出一个错误，其结果如下所示：

$db = JFactory::getDBO();
$query = "SHOW COLUMNS FROM `#__facets` LIKE 'filters'";
$db->setQuery($query);
$res = $db->loadResult();

代码： -

ConnectionResult{statusCode=SIGN_IN_REQUIRED, resolution=PendingIntent{425b8550: android.os.BinderProxy@423ec2e8}, message=null}

Answer 1

您可以尝试以下代码：首先，您需要将GoogleApi初始化为：

private void googleInitialization() {
    GoogleSignInOptions gso = new GoogleSignInOptions.Builder(GoogleSignInOptions.DEFAULT_SIGN_IN)
            .requestEmail()
            .build();
    mGoogleApiClient = new GoogleApiClient.Builder(this)
            .enableAutoManage(this, this)
            .addApi(Auth.GOOGLE_SIGN_IN_API, gso)
            .build();
    mGoogleApiClient.connect();


}

之后你需要像这样调用这个方法： -

googleInitialization();
                    Intent signInIntent = Auth.GoogleSignInApi.getSignInIntent(mGoogleApiClient);
                    startActivityForResult(signInIntent, RC_SIGN_IN);

并且OnActivityResult中的句柄有一个 CallBackManager ，这对于调用登录按钮非常有用

  @Override
    public void onActivityResult(int requestCode, int resultCode, Intent data) {
        super.onActivityResult(requestCode, resultCode, data);
        callbackManager.onActivityResult(requestCode, resultCode, data);

        if (requestCode == RC_SIGN_IN) {
            GoogleSignInResult result = Auth.GoogleSignInApi.getSignInResultFromIntent(data);
            handleSignInResult(result);
        }
    }

现在，获得以下方法的结果：

 private void handleSignInResult(GoogleSignInResult result) {
        Log.d("handleSignInResult", "handleSignInResult:" + result.isSuccess());
        if (result.isSuccess()) {
            // Signed in successfully, show authenticated UI.
            GoogleSignInAccount acct = result.getSignInAccount();
            String personName = acct.getDisplayName();
            String email = acct.getEmail();
            if (personName.contains(" ")) {
              String  fname = personName.substring(0, personName.lastIndexOf(" ") + 1);
             String     lname = personName.substring(personName.lastIndexOf(" ") + 1);
                Log.e("First name", fname);
                Log.e("Last name", lname);
            } else
              String    fname = personName;

            Log.e("Profile Info", "Name: " + personName + ", email: " + email);
        }
    }

如何解决google plus Integration中的SIGN_IN_REQUIRED错误？

1 个答案: