Question

我在postgres表中有一个金额，我可以通过查询select sum (price) from xyz我想在不同的级别转换这个值，就像我将它转换为

Price > 2000
1000  - 2000
500   - 1000
Price < 500

我想在网站的过滤器中显示它...我正在使用（postgres，codeiginiter，javascript，jquery）可以使用任何语言帮助我创建该格式

Answer 1

finaly create thanx to all

 select t1.row_number,t1.left,t2.right from
(SELECT row_number() over(),f2.* from(
SELECT generate_series(max(purchase_price::integer) , min(purchase_price::integer),-((max(purchase_price::integer))/5)) AS left FROM tbl_products) f2) t1
join
(SELECT row_number() over(),f.* from(
(SELECT  generate_series(max(purchase_price::integer) , min(purchase_price::integer),-((max(purchase_price::integer))/5)) AS right FROM tbl_products offset 1)
union all
(select '0' as right)) f)t2
on t1.row_number =t2.row_number

Answer 2

我有这个查询<form [FormGroup]="form" (ngSubmit)="onSubmit(form.value)"> <input type="text" placeholder="firstname" name="firstname" formControlName="firstname" /> <br> <input type="text" placeholder="lastname" name="lastname" formControlName="lastname" /> <br> <select name="languages" formControlName="languages"> <option value="C++">C++</option> <option value="Java">Java</option> <option value="Angular">Angular</option> </select> <br><br> <input type="submit" value="submit" /> </form> ....左右列显示相同的值...我只想要右列开始第二个值，最后一行显示0

你为什么要用SQL做这件事？

像

这样的东西

＆＃13;

SELECT generate_series(10000 , 2001,-((10000)/5)) AS left, generate_series(10000 , 2001,-((10000)/5)) AS right

＆＃13;

var arr = [];
for(var i=10000; i >= 2001; ) 
   arr.push([i, i -= 10000/5]);
   
console.log(arr);

＆＃13;

.as-console-wrapper{top:0;max-height:100%!important}与... and last row show 0的结束值相矛盾。您的函数调用将生成系列2001，甚至不存在2000。那么一个人呢？ 0或2001？

或者，如果以前的代码看起来像＃34; hacky＆＃34;对你：

[10000, 8000, 6000, 4000]

将值转换为不同的级别

2 个答案: