Question

我有一个像这样的字符串 [ “1505213753057”， “1505213854042”， “1505537148455”]

我想将其拆分并将值存储到Long Array中。

String [] loanId = loanIds.split("\"?,(?=(?:(?:[^\"]*\"){2})*[^\"]*$)\"?");
                Long[] data = new Long[loanId.length];
                for (int i = 0; i < loanId.length; i++) {
                    data[i] = Long.parseLong(loanId[i]);
                }

我正在使用这个分离器，但它不起作用。任何帮助如何实现这一目标？

Answer 1

这应该有效

String loanIds = "[\"1505213753057\",\"1505213854042\",\"1505537148455\"]";

loanIds = loanIds.replaceAll("(\\[\")|(\"\\])", "").replaceAll("\",\"", ",");
String [] loanId = loanIds.split(",");
Long[] data = new Long[loanId.length];
for (int i = 0; i < loanId.length; i++) {
    data[i] = Long.parseLong(loanId[i]);
    System.out.println(data[i]);
}

Answer 2

将[和]替换为{和}。

import java.util.*;
class check {
    public static void main(String ar[]){ 
        String str[] ={"1505213753057","1505213854042","1505537148455"};
        long ll[]=new long[str.length];
        for(int i=0;i<str.length;i++)
            ll[i]=Long.parseLong(str[i]);
        for(int i=0;i<str.length;i++)
            System.out.println(ll[i]);
         }
     }

Answer 3

这可以使用正则表达式实现，如下所示：

package com.grsdev.stackoverflow.question170920.pack01;

import java.util.ArrayList;
import java.util.Collections;
import java.util.List;
import java.util.regex.Matcher;
import java.util.regex.Pattern;


public class LongNumerString {

    public static void main(String[] args) {


        String text="[\"1505213753057\",\"1505213854042\",\"1505537148455\"]";

        Pattern pattern=Pattern.compile("\\d+");

        Matcher matcher = pattern.matcher(text);


        List<Long> list=new ArrayList<>(); 

        while(matcher.find()){
            list.add(Long.valueOf(matcher.group()));
        }


        System.out.println("longs  : "+list);



        Long [] array = new Long[list.size()];

        list.toArray(array);
    }

}

Answer 4

mainstring = [＆＃34; 1505213753057＆＃34;＆＃34; 1505213854042＆＃34;＆＃34; 1505537148455＆＃34;] 这是你的字符串吗？

如果是，并且您想要将所有元素存储在长数组中，那么这个myt就是解决方案

String stringWithoutBraces = mainstring.substring（1，mainstring.length（） - 1）;

        List<Long> loanidlist=new ArrayList<>();
        String[] stringWithoutCommas=stringWithoutBraces.split(",");

        for(String splited:stringWithoutCommas){
            String eachElement=splited.substring(1,splited.length()-1);
            loanidlist.add(Long.parseLong(eachElement));
        }
        Long[] loanid=(Long[]) loanidlist.toArray(new Long[loanidlist.size()]);

split string input包含基于逗号双引号和括号的长数字

4 个答案: