Question

我选择开始日期和结束日期，订单状态，然后我列出了我的表格中的订单。

最后一栏表示该日期有多少订单。我想得到一个数字，根本就有多少订单。我的意思是：从2017-01-01到2017-01-31，共有127个订单。

如果我们使用我的照片，结果将是49顺序。

SELECT datum, COUNT(rendeles_id) AS ennyi FROM rendeles_adatok 

                            WHERE datum >= '$date_start' AND (datum <= '$date_end' AND status = $rendeles_allapot)

                        GROUP BY datum ORDER BY $kereses_sorrend

完整代码

$date_start = mysqli_real_escape_string($kapcs, $_POST['date_start']);
                $date_end = mysqli_real_escape_string($kapcs, $_POST['date_end']);
                $rendeles_allapot = mysqli_real_escape_string($kapcs, $_POST['rendeles_allapot']);
                $kereses_sorrend = mysqli_real_escape_string($kapcs, $_POST['kereses_sorrend']);

                if($rendeles_allapot != 1234 )
                {
                    $sql = "
                        SELECT datum, COUNT(rendeles_id) AS ennyi FROM rendeles_adatok 

                            WHERE datum >= '$date_start' AND (datum <= '$date_end' AND status = $rendeles_allapot)

                        GROUP BY datum ORDER BY $kereses_sorrend
                   ";
                }
                else
                {
                    $sql = "
                        SELECT datum, COUNT(rendeles_id) AS ennyi FROM rendeles_adatok 

                            WHERE datum >= '$date_start' AND datum <= '$date_end'

                        GROUP BY datum ORDER BY datum ASC
                   ";
                }
               //printr($sql);

               echo '<table class="table table-hover table-bordered list">';
                echo '<thead>
                      <tr>
                        <td class="left">Kezdő dátum</td>                           
                        <td class="left">Záró dátum</td>
                        <td class="center">Vásárlások száma</td>
                      </tr>
                    </thead>';
                echo '<tbody>';
               $hirek_down = mysqli_query($kapcs, $sql) or die(mysqli_error($kapcs));
               $talalatok = mysqli_num_rows($hirek_down);
               $fetch_count = mysqli_fetch_assoc($hirek_down);
               if($talalatok > 0 )
               {
                   echo '<p>Összesen '.$fetch_count['ennyi'].' találat.</p>';
                   echo '<p>Total sum: </p>';
                   while($a = mysqli_fetch_assoc($hirek_down))
                    {
                        echo '<tr>
                                <td class="left">'.html($a['datum']).'</td>
                                <td class="left">'.html($a['datum']).'</td>
                                <td class="center">'.html($a['ennyi']).'</td>
                             </tr>';
                    }
                   echo '</tbody>';
                   echo '</table>';
               }

Answer 1

您必须使用SUM（）来获取该列的总和。

SELECT datum, SUM(rendeles_id) AS ennyi FROM rendeles_adatok 

                        WHERE datum >= '$date_start' AND (datum <= '$date_end' AND status = $rendeles_allapot)

                    GROUP BY datum ORDER BY $kereses_sorrend

COUNT（）只会计算与搜索匹配的行数，而SUM（）会添加指定列的值。

Answer 2

您的查询将如下所示：

SELECT datum, COUNT(rendeles_id) AS num_rows,
       SUM(num_orders) as num_orders
FROM rendeles_adatok 
WHERE datum >= '$date_start' AND (datum <= '$date_end' AND status = $rendeles_allapot)
GROUP BY datum
ORDER BY $kereses_sorrend;

注意：每天订单的计数通常不会被称为_id（至少用英语和我熟悉的其他语言）。我不知道您的列名称是什么，但您想要sum()。

在mysql中计算或求和一个字段

2 个答案: